2016-02-26 99 views
0

我有以下格式的数据:angularjs过滤了深刻的JSON对象

{ 
    "A": { 
    "P": { 
     "Age": { 
     "keyName": "Repo1", 
     "checked": false 
     }, 
     "Gender": { 
     "keyName": "Repo2", 
     "checked": false 
     } 
    } 
    }, 
    "S": { 
    "D": { 
     "keyName": "Repo3", 
     "checked": false 
    }, 
    "W": { 
     "keyName": "Repo4", 
     "checked": false 
    } 
    } 
} 

HTML:

<div ng-controller="MyController"> 
    <ul> 
    <li ng-repeat="kName in keyNames"> 
     <input type="checkbox" value="{{kName.keyName}}" ng-click="selectedKeyNames($event, kName)"> {{kName.keyName}} 
     </li> 
    </ul> 

    <pre>{{tempData | json}}</pre> 
</div> 

JS:

var myApp = angular.module('myApp', []); 

myApp.controller('MyController',["$scope","$filter", function ($scope, $filter) { 

    $scope.tempData = {"A":{"P":{"Age":{"keyName":"Repo1","checked":false},"Gender":{"keyName":"Repo2","checked":false}}},"S":{"D":{"keyName":"Repo3","checked":false},"W":{"keyName":"Repo4","checked":false}}}; 

$scope.keyNames = $filter("buildKeyMap")($scope.tempData); 

$scope.selectedKeyNames = function(e, rpt){ 
    $scope.findNode($scope.tempData, "keyName", rpt.keyName, $(e.target).is(":checked")); 

}; 

     $scope.findNode = function(obj, key, val, isChecked) { 
      var objects = []; 
      for (var i in obj) { 
       if (!obj.hasOwnProperty(i)) continue; 
       if (typeof obj[i] == 'object') { 
        objects = objects.concat($scope.findNode(obj[i], key, val, isChecked)); 
       } else if (i == key && obj[key] && obj[key] == val) { 
        obj.checked = isChecked; 
        $scope.foundObject = obj; 
        break; 
       } 
      } 
      return $scope.foundObject; 
     }; 

}]).filter("buildKeyMap",function(){ 
     return function(items){ 
      var options = [] 
      var recursiveFilter = function(items){ 
       angular.forEach(items, function(item, parentKey){ 
        if(item.hasOwnProperty("keyName")){ 
         options.push({"keyName": item.keyName}); 
        }else{ 
         recursiveFilter(item); 
        } 
       }); 
      }; 
      recursiveFilter(items); 
      return options; 
     }; 
    }); 

,我想只过滤那些节点其中checked = true。它应该是在相同的JSON结构。我已经完成了checked = true,但我无法从json中删除或添加节点。

这里是小提琴: http://jsfiddle.net/qsp4dwsd/5/ 它设置检查= true,但JSON保持不变的情况下,假意或真心

+0

你控制从后端初始数据结构?如果使用阵列结构,会更简单 – charlietfl

+0

@charlietfl:请问你可以用数组结构来解决吗?谢谢 – maverickosama92

+0

如果您确实控制后端,则使用所有对象的标准化键发回对象数组。您有几个深度级别,因此嵌套具有相同对象结构的“children”数组也是如此。然后你可以使用嵌套'ng-repeat' – charlietfl

回答

1

这里我创建了工作demo

总体变化:

  • 定义NG-模型复选框
  • 定义的变量OrginalData
  • 更改selectedKeyNames方法
  • 更改find​​Node方法

HTML

<div ng-controller="MyController"> 
    <ul> 
    <li ng-repeat="kName in keyNames"> 
     <input type="checkbox" ng-model="kName.checked" value="{{kName.keyName}}" ng-click="selectedKeyNames()"> {{kName.keyName}} 
     </li> 
    </ul> 

    <pre>{{tempData | json}}</pre> 
</div> 

JS

var myApp = angular.module('myApp', []); 

myApp.controller('MyController',["$scope","$filter", function ($scope, $filter) {  

var OriginalData ={"A":{"P":{"Age":{"keyName":"Repo1","checked":false},"Gender":{"keyName":"Repo2","checked":false}}},"S":{"D":{"keyName":"Repo3","checked":false},"W":{"keyName":"Repo4","checked":false}}} 

$scope.tempData = $.extend(true, {}, OriginalData); 

$scope.keyNames = $filter("buildKeyMap")($scope.tempData); 

$scope.selectedKeyNames = function(e, rpt){ 
    $scope.tempData = $.extend(true, {}, OriginalData); 
    for(var kName in $scope.keyNames){ 
    $scope.findNode($scope.tempData, "keyName", $scope.keyNames[kName].keyName, $scope.keyNames[kName].checked); 
    } 
}; 

     $scope.findNode = function(obj, key, val, isChecked) { 
      for (var i in obj) { 
       if (!obj.hasOwnProperty(i)) continue; 
       if (typeof obj[i] == 'object') { 
       $scope.findNode(obj[i], key, val, isChecked); 
       } 
       else if (i == key && obj[key] && obj[key] == val)        {     
         if(!isChecked) { 
         delete obj[i]; 
         delete obj["checked"]; 
        } 
        else 
         obj.checked = isChecked; 
        break; 
       } 
      }    
     }; 

}]).filter("buildKeyMap",function(){ 
     return function(items){ 
      var options = [] 
      var recursiveFilter = function(items){ 
       angular.forEach(items, function(item, parentKey){ 
        if(item.hasOwnProperty("keyName")){ 
         options.push({"keyName": item.keyName}); 
        }else{ 
         recursiveFilter(item); 
        } 
       }); 
      }; 
      recursiveFilter(items); 
      return options; 
     }; 
    }); 
+0

谢谢,但另外你也可以删除空的json {}节点吗? – maverickosama92

+0

我已经想通了,谢谢你。 – maverickosama92

+0

maverickosama92:不客气。 – amighty

1

我可以帮助更多有究竟是如何做到这一点可以随意给我发短信,但简单的答案是在过滤器这一大包:

https://github.com/a8m/angular-filter#filterby

通过过滤器有助于正是你正在尝试做的,不过我建议你转换顶层对象到一个数组第一。

collection | filterBy: [prop, nested.prop, etc..]: search: strict[optional] 

希望这会有所帮助。

+0

我不能改变我的json格式。 – maverickosama92

+0

肖恩:请问你可以用数组结构来解决吗?谢谢 – maverickosama92