如何检查字符串中的单词是否是列表或列表中的元素？

Question

test_string = ("this is a test") 

test_list = [dog, cat, test, is, water] 

我如何看待'this'或'是'或'a'或'test'是否在test_list中？

Answer 1

使用str.split分割字符串，并使用any，看看是否有任何字符串中的话您的列表：

test_string = ("this is a test") 

test_list = ["dog", "cat", "test", "is","water"] 
print(any(x in test_list for x in test_string.split())) 



In [9]: test_string = ("this is a test") 

In [10]: test_string.split() 
Out[10]: ['this', 'is', 'a', 'test'] # becomes a list of individual words 

Answer 2

您可以使用any这个

inlist = any(ele in test_list for ele in test_string.split())

inlist将是真或假，取决于它是否在列表中。

例子：

>>test_string = ("this is a test") 
>>test_list = ['dog', 'cat', 'water'] 
>>inlist = any(ele in test_string for ele in test_list) 
>>print inlist 
False 

>>test_string = ("this is a test") 
>>test_list = ['dog', 'cat', 'is', 'test' 'water'] 
>>inlist = any(ele in test_string for ele in test_list) 
>>print inlist 
True 

Answer 3

什么你问的是交集仅仅是空的。

>>> set(test_string.split(' ')).intersection(set(test_list)) 
set(['test', 'is']) 

Answer 4

一种选择是正则表达式，如

import re 

# Test string 
test_string = 'this is a test' 

# Words to be matched 
test_list = ['dog', 'cat', 'test', 'is', 'water'] 

# Container for matching words 
yes = [] 

# Loop through the list of words 
for words in test_list: 
    match = re.search(words, test_string) 
    if match: 
     yes.append(words) 

# Output results 
print str(yes) + ' were matched' 

#['test', 'is'] were matched