我很努力地做这个工作,基本上我从前面的活动中使用intent得到一个id,现在我想把这个id发送到服务器,所以它返回所有关联的数据与此ID。android volley post json ID并从PHP服务器获取结果
javacode
final String URL = "URL";
// Post params to be sent to the server
HashMap<String, String> params = new HashMap<String, String>();
params.put("ID", "1");
JsonObjectRequest req = new JsonObjectRequest(URL, new JSONObject(params),
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
VolleyLog.v("Response:%n %s", response.toString(4));
print response in textview;
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.e("Error: ", error.getMessage());
}
});
// add the request object to the queue to be executed
ApplicationController.getInstance().addToRequestQueue(req);
PHP服务器
if (!empty($_POST)) {
$query = " SELECT * FROM table WHERE ID = :ID " ;
$query_params = array(
':ID' => $_POST['ID'],);
try {
$statement = $db->prepare($query);
$result = $statement->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database query error";
die(json_encode($response));
}
$result = $statement->fetchAll();
if($result){
$data =array();
foreach($result as $rows){
$json = array();
$json["Name"] = $rows["Name"];
array_push ($data,$json);
}
echo stripcslashes(json_encode($data, JSON_PRETTY_PRINT));
到底什么是你的错误吗?它会返回什么吗? –