1
说我有这个如何检查矢量中的两个元素是否按顺序排列?
vector<int>SequentialByOne{1, 2, 3, 4, 5} //would like to search each element
//in the vector and if it is sequential a boolean value returns true
vector<int>notSequential{1, 6, 5, 8, 9} // This would return false
vector<int>notSequentialButOrdered{1, 3, 6, 9, 20} // This would return false
// So far I can get it to return true if the next number
// is bigger than the previous but can't figure out
// how to check that the next number is only one bigger.
这是一个扑克手电梯我工作的学校项目。我有一个有序的5个数字的矢量,现在我需要搜索该矢量以查找它们是否按照精确的顺序+1。
这是我到目前为止
sort(hand.begin(), hand.end()); // This is the vector name
int a;
{
for(int i = 0; i < 4; i++)
{
if(hand[i] < hand[i + 1] - 1)
a++;
}
}
bool has_straight
{
if(a == 5)
return true;
}
不太清楚是什么问题。如果你想检查平等而不是不平等,那么就做,如果(手[I] =手[I + 1] + 1)'而不是'如果(手[I] <手[I + 1] - 1)' – user463035818
检查'hand [i + 1] - hand [i] == 1'?或者说,检查'hand [i + 1] - hand [i]!= 1',如果是true,则返回false。 –
你现在的代码有什么问题?如果您希望某人查看您的代码,请访问:https://codereview.stackexchange.com/ – Lanting