在SQLSERVER

Question

拆分的方法是有没有办法在SQL Server nvarchar的分裂看起来像这样：

'some text[tag1][tag2] [tag3]' 

到：

[tag1] 
[tag2] 
[tag3] 

？

p.s. 我更新了示例数据以显示没有严格的分隔符。我需要将所有内容都放在括号内！

Answer 1

下面尝试。

declare @v varchar(1000) 
set @v = '[1212][12121212]  [[[' 

create table #temp 
(
    v varchar(1000) 
) 
--insert into #temp(v)values(@v) 

declare @Firstindex int 
declare @Secondindex int 

declare @subval varchar(100) 

Set @Firstindex = charindex('[', @v, 1) 
while(@Firstindex <> 0) 
Begin 
    Set @Firstindex = charindex('[', @v, @Firstindex) 

    if(@Firstindex = 0) 
     break 

    Set @Secondindex = charindex(']', @v, @Firstindex) 

    if(@Secondindex = 0) 
     break; 
    if(@Firstindex + 1 <> @Secondindex) 
    Begin 
     set @subval = substring(@v, @Firstindex + 1, (@Secondindex - 1) - (@Firstindex)) 
     select @subval 
     Insert into #temp values(@subval) 
    End 
    set @Firstindex = @Secondindex 

End 

select * from #temp 
drop table #temp 

Answer 2

可以使用下面的函数

CREATE FUNCTION [dbo].[fnSplit]( 
    @sInputList VARCHAR(8000) 
    , @sDelimiter VARCHAR(8000) = ',' 
) RETURNS @List TABLE (ID VARCHAR(8000)) 

BEGIN 
DECLARE @sItem VARCHAR(8000) 
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0 
BEGIN 
SELECT 
    @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))), 
    @sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList)))) 

IF LEN(@sItem) > 0 
    INSERT INTO @List SELECT @sItem 
END 

IF LEN(@sInputList) > 0 
INSERT INTO @List SELECT @sInputList 
RETURN 
END 

输出可以像

SELECT * FROM dbo.fnSplit（ '[12] [12] [13]'，”“）

进行验证

它会显示

12 
12 
13