需要方法返回XElement而不是字节[]

Question

我有以下方法，我需要返回一个XElement。问题是，无法弄清楚如何将byte[]转换为XElement。

public XElement ServiceCallForNewMadidPlantReport() 
{ 
    var kpiReportClient = new ReportExecutionService(); 
    kpiReportClient.Credentials = System.Net.CredentialCache.DefaultCredentials; 
    var endPoint = new EndpointAddress("*****"); 
    kpiReportClient.Url = endPoint.ToString(); 

    //render arguments 
    byte[]result = null; 
    string reportSickTimePlants = "/Human Resources/KPI POW/Kpi_Fmla_Summarized_Plants_Prg"; //report path 
    string format = "XML"; 
    string historyID = null; 
    string devInfo = ""; 

    //prepare report parameter 
    ParameterValue[] parameters = new ParameterValue[4]; 
    parameters[0] = new ParameterValue(); 
    parameters[0].Name = "Location"; 
    parameters[0].Value = "4"; //New Madrid 
    parameters[1] = new ParameterValue(); 
    parameters[1].Name = "UnCode"; 
    parameters[1].Value = "Non-Union"; 
    parameters[2] = new ParameterValue(); 
    parameters[2].Name = "StartDate"; 
    parameters[2].Value = "01/01/2006"; 
    parameters[3] = new ParameterValue(); 
    parameters[3].Name = "EndDate"; 
    parameters[3].Value = "08/08/2012"; 

    string encoding; 
    string mimeType; 
    string extension; 
    Warning[] warnings = null;    
    string[] streamIDs; 

    ExecutionInfo execInfo = new ExecutionInfo(); 
    ExecutionHeader execHeader = new ExecutionHeader(); 
    kpiReportClient.ExecutionHeaderValue = execHeader; 

    var trustedUserHeader = new TrustedUserHeader();    

    execInfo = kpiReportClient.LoadReport(reportSickTimePlants, historyID); 

    kpiReportClient.SetExecutionParameters(parameters, "en-us"); 

    String SessionId = kpiReportClient.ExecutionHeaderValue.ExecutionID; 

    Console.WriteLine("SessionID: {0}", kpiReportClient.ExecutionHeaderValue.ExecutionID); 

    try 
    { 
     result = kpiReportClient.Render(format, devInfo, out extension, out encoding, out mimeType, out warnings, out streamIDs); 
     Console.WriteLine(result); 
     execInfo = kpiReportClient.GetExecutionInfo(); 
    } 
    catch (SoapException e) 
    { 
     Console.WriteLine(e.Detail.OuterXml); 
    } 
    try 
    { 
     FileStream sickTimReportForPlants = File.Create("SickTimeNonRepEmpReport.xml", result.Length); 
     Console.WriteLine("File created."); 
     Console.WriteLine(sickTimReportForPlants); 
     sickTimReportForPlants.Write(result, 0, result.Length); 
     Console.WriteLine("Result written to the file.");     
     sickTimReportForPlants.Close(); 
    } 
    catch (Exception e) 
    { 
     Console.WriteLine(e.Message); 
    } 
    return ? (must be XElement) 
} 

这是我已经试过，但它不工作：

​​

这给了我下面的错误：

System.Xml.XmlException: Data at the root level is invalid. Line 1, position 1.

我尝试了其他几个方面也但无论我做什么，我都会得到同样的错误。这里是xml文件的样子：

<?xml version="1.0" encoding="utf-8"?><Report xsi:schemaLocation="Kpi_Fmla_Summarized_Plants_Prg http://gonzo/ReportServer?%2fHuman+Resources%2fKPI+POW%2fKpi_Fmla_Summarized_Plants_Prg&amp;rs%3aFormat=XML&amp;rc%3aSchema=True" Name="Kpi_Fmla_Summarized_Plants_Prg" Location="New Madrid" Textbox84="KPI SICK/FMLA 1/1/2006 12:00:00 AM - 8/8/2012 12:00:00 AM" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="Kpi_Fmla_Summarized_Plants_Prg"><Tablix1><Textbox13><Textbox3><Textbox15 /></Textbox3></Textbox13><Category_Collection><Category Category1="FMLA"><represented1_Collection><represented1 represented11="Non-Union"><QTR_Collection><QTR QTR1="1" Textbox27="1787" /><QTR QTR1="2" Textbox27="988.75" /><QTR QTR1="3" Textbox27="1577.75" /><QTR QTR1="4" Textbox27="2133.25" /></QTR_Collection></represented1></represented1_Collection></Category><Category Category1="Sick"><represented1_Collection><represented1 represented11="Non-Union"><QTR_Collection><QTR QTR1="1" Textbox27="5407.5" /><QTR QTR1="2" Textbox27="4051.75" /><QTR QTR1="3" Textbox27="3928" /><QTR QTR1="4" Textbox27="4204.75" /></QTR_Collection></represented1></represented1_Collection></Category></Category_Collection></Tablix1></Report>  

我不知道我在做什么错。

编辑：

后做了以下内容：

string resultFromBytes = UTF8Encoding.UTF8.GetString(result); 
return XDocument.Parse(resultFromBytes).Root; 

我仍然得到同样的错误信息，但这里是resultFromBytes我的XML

<?xml version="1.0" encoding="utf-8"?><Report xsi:schemaLocation="Kpi_Fmla_Summarized_Plants_Prg http://gonzo/ReportServer?%2fHuman+Resources%2fKPI+POW%2fKpi_Fmla_Summarized_Plants_Prg&amp;rs%3aFormat=XML&amp;rc%3aSchema=True" Name="Kpi_Fmla_Summarized_Plants_Prg" Location="New Madrid" Textbox84="KPI SICK/FMLA 1/1/2006 12:00:00 AM - 8/8/2012 12:00:00 AM" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="Kpi_Fmla_Summarized_Plants_Prg"><Tablix1><Textbox13><Textbox3><Textbox15 /></Textbox3></Textbox13><Category_Collection><Category Category1="FMLA"><represented1_Collection><represented1 represented11="Non-Union"><QTR_Collection><QTR QTR1="1" Textbox27="1787" /><QTR QTR1="2" Textbox27="988.75" /><QTR QTR1="3" Textbox27="1577.75" /><QTR QTR1="4" Textbox27="2133.25" /></QTR_Collection></represented1></represented1_Collection></Category><Category Category1="Sick"><represented1_Collection><represented1 represented11="Non-Union"><QTR_Collection><QTR QTR1="1" Textbox27="5407.5" /><QTR QTR1="2" Textbox27="4051.75" /><QTR QTR1="3" Textbox27="3928" /><QTR QTR1="4" Textbox27="4204.75" /></QTR_Collection></represented1></represented1_Collection></Category></Category_Collection></Tablix1></Report> 

编辑：

后这样做：

string resultFromBytes = UTF8Encoding.UTF8.GetString(result); 
var regex = new System.Text.RegularExpressions.Regex(@"xsi:schemaLocation="".+"""); 
string strippedxml = regex.Replace(resultFromBytes, ""); 
return XDocument.Parse(strippedxml).Root; 

我得到同样的失败。这是strippedxml的样子：

<?xml version="1.0" encoding="utf-8"?><Report /></QTR_Collection></represented1></represented1_Collection></Category></Category_Collection></Tablix1></Report> 

编辑：

尝试这样做，XML看起来好多了，但还是失败，同样的错误：

string resultFromBytes = UTF8Encoding.UTF8.GetString(result); 
var regex = new System.Text.RegularExpressions.Regex(@"xsi:schemaLocation="".+"""); 
string strippedxml = regex.Replace(resultFromBytes, ""); 
return XDocument.Parse(strippedxml).Root; 

这里就是从strippedxml的XML是什么样子：

<?xml version="1.0" encoding="utf-8"?><Report Name="Kpi_Fmla_Summarized_Plants_Prg" Location="New Madrid" Textbox84="KPI SICK/FMLA 1/1/2006 12:00:00 AM - 8/8/2012 12:00:00 AM" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="Kpi_Fmla_Summarized_Plants_Prg"><Tablix1><Textbox13><Textbox3><Textbox15 /></Textbox3></Textbox13><Category_Collection><Category Category1="FMLA"><represented1_Collection><represented1 represented11="Non-Union"><QTR_Collection><QTR QTR1="1" Textbox27="1787" /><QTR QTR1="2" Textbox27="988.75" /><QTR QTR1="3" Textbox27="1577.75" /><QTR QTR1="4" Textbox27="2133.25" /></QTR_Collection></represented1></represented1_Collection></Category><Category Category1="Sick"><represented1_Collection><represented1 represented11="Non-Union"><QTR_Collection><QTR QTR1="1" Textbox27="5407.5" /><QTR QTR1="2" Textbox27="4051.75" /><QTR QTR1="3" Textbox27="3928" /><QTR QTR1="4" Textbox27="4204.75" /></QTR_Collection></represented1></represented1_Collection></Category></Category_Collection></Tablix1></Report> 

Answer 1

我有答案。我试图将它从byte []转换为XElement。相反，我将它转换成流，然后将其转换为Xelement。像这样：

result = kpiReportClient.Render(format, devInfo, out extension, out encoding, out mimeType, out warnings, out streamIDs); 
Console.WriteLine(result); 
result = kpiReportClient.Render(format, devInfo, out extension, out encoding, out mimeType, out warnings, out streamIDs); 
Stream resStream = new MemoryStream(result); 
var nonRepSickReportForNM = XElement.Load(resStream); 
return nonRepSickReportForNM 

虽然我不能赞扬它。我的老板弄明白了。

Answer 2

也许沿着这条线：（修复名称空间的麻烦）

string resultFromBytes = UTF8Encoding.UTF8.GetString(result); 

var nt = new NameTable(); 
var nsmgr = new XmlNamespaceManager(nt); 
nsmgr.AddNamespace(String.Empty, "urn:samples"); //default namespace 
nsmgr.AddNamespace("xsi", "urn:samples2"); // xsi fix 

var context = new XmlParserContext(nt, nsmgr,null, XmlSpace.None); 

var settings = new XmlReaderSettings(); 
settings.ConformanceLevel = ConformanceLevel.Document; 

var xrdr= XmlReader.Create(new StringReader(xml), settings, context); 
return XDocument.Load(xrdr).Root;