一种技术,你可以做是加入两个表,并使用SELECT GROUP_CONCAT作为一个单一的变量连接值,是的,你可以爆炸()稍后打破它们。
实际上使用GROUP_CONCAT,这是你可以做什么:
mysql> SELECT f.name, GROUP_CONCAT(a.url SEPARATOR ",") AS awards FROM film f JOIN awards a ON a.film_id = f.id;
+-----------------------+-----------------------------------------------------------------------------+
| name | awards |
+-----------------------+-----------------------------------------------------------------------------+
| River Runs Through It | http://www.ariverrunsthroughit.com,http://www.webby.com,http://www.imdb.com |
+-----------------------+-----------------------------------------------------------------------------+
1 row in set (0.00 sec)
mysql>
在PHP中,你使用上面的查询查询数据库,并说这是一个变量,名为$行输出,那么你可以如您注意到的那样,将奖励变量分解并输出到单独的DIVS中。
<?php
// connection
$query = mysql_query("SELECT f.name, GROUP_CONCAT(a.url SEPARATOR ",") AS awards FROM film f JOIN awards a ON a.film_id = f.id");
while ($row = mysql_fetch_array($query)) {
$title = $row['name'];
// get awards
$awards = explode(",", $row['awards']);
// output title and awards (iterate through array)
echo "<hr>";
echo "<div id='title'>$title</div>";
foreach ($awards AS $award) {
echo "<div id='award'>$award</div>";
}
}
这里是SQL来构建测试:
mysql> create table film (id INT AUTO_INCREMENT, name VARCHAR(24), PRIMARY KEY (id));
Query OK, 0 rows affected (0.00 sec)
mysql> INSERT INTO film VALUES (1, "River Runs Through It");
Query OK, 1 row affected (0.00 sec)
mysql> CREATE TABLE awards (id INT AUTO_INCREMENT, film_id INT NOT NULL, url VARCHAR(64), title VARCHAR(24), PRIMARY KEY (id));
Query OK, 0 rows affected (0.01 sec)
mysql> INSERT INTO awards VALUES (1,1,'http://www.ariverrunsthroughit.com','Our Award'), (2,1,'http://www.webby.com', 'Webby Award'), (3,1,'http://www.imdb.com', 'IMDB Award');
Query OK, 3 rows affected (0.01 sec)
Records: 3 Duplicates: 0 Warnings: 0
感谢这似乎工作与一些小调整。 – Tom 2012-07-24 20:12:38