加班费的awk计算

Question

对于下面的数据，我试图确定随着时间的推移，总共会使用awk文件。 （加班规则：如果超过40小时的工作，每一个小时后，获得1.5倍的工资）

Natlie Attired 902-555-1234 10.40 44 
Guy Wyre 401-555-3421 11.75 40 

这是我迄今为止

BEGIN{ 
    FS=" " 
} 
function total(){ 
    hours = awk {print $5} 
    rate = awk {print $4} 
    if(hours<=40) 
     sum=rate*hours 
     return sum 
    else 
     sum=(hours - 40 * 1.5 * rate) + (rate*hours) 
     return sum 
} 

{ 
    printf("%s %s worked %d hours, for a total pay of %.2f.\n", $1, $2,$5, total()) 
} 

我需要什么，以改变这产生一个准确的答案？

Answer 1

为了使执行没有错误，我只好：

• 删除awk {print ...}周边$5和$4
• 加括号的if-then-else语句

要使计算正确，我不得不：

• put p各地hours - 40
• arentheses通过0.5更换1.5（或者，通过(rate * 40)更换(rate * hours)）

结果代码：

function total() { 
    hours = $5; 
    rate = $4; 
    if (hours <= 40) { 
     sum = rate * hours; 
     return sum; 
    } 
    else { 
     sum = ((hours - 40) * 0.5 * rate) + (rate * hours); 
     return sum; 
    } 
} 

{ 
    printf("%s %s worked %d hours, for a total pay of %.2f.\n", $1, $2, $5, total()); 
} 

输出：

Natlie Attired worked 44 hours, for a total pay of 478.40. 
Guy Wyre worked 40 hours, for a total pay of 470.00. 

Answer 2

$ cat tst.awk 
function total( regHours, otHours, rate, sum){ 
    rate = $4 
    regHours = $5 
    if (regHours > 40) { 
     otHours = regHours - 40 
     regHours = 40 
    } 
    sum = ((otHours * 1.5) + regHours) * rate 
    return sum 
} 

{ 
    printf "%s %s worked %d hours, for a total pay of %.2f.\n", $1, $2, $5, total() 
} 
$ 
$ awk -f tst.awk file 
Natlie Attired worked 44 hours, for a total pay of 478.40. 
Guy Wyre worked 40 hours, for a total pay of 470.00.