-1
我创建了一个提交给php页面的AJAX表单。这张表格已成功提交,我收到了我的数据库中的电子邮件地址,并且发送了一封确认电子邮件。Ajax表单提交成功但出现提示错误
不过,我得到一个警告消息,指出“错误|”,所以很明显它是从这个未来:
error: function (xhr, textStatus, errorThrown) {
alert(textStatus + "|" + errorThrown);
我不清楚为什么,如果它工作的错误是扔的。另一件事,这种形式是重新加载页面。我有event.preventDefault();
,所以为什么要重新加载页面?
我很感激任何帮助。
<form action="" method="POST">
<input type="email" id="footer-grid1-newsletter-input" placeholder="Your Email Address">
<input type="submit" id="footer-grid1-newsletter-submit" name="submit">
</form>
$(document).ready(function(){
$("#footer-grid1-newsletter-submit").on("click", function() {
event.preventDefault();
var newsletter_email = $("#footer-grid1-newsletter-input").val();
$.ajax({
url: "newsletterSend.php",
type: "POST",
data: {
"newsletter_email": newsletter_email
},
success: function (data) {
// console.log(data); // data object will return the response when status code is 200
if (data == "Error!") {
alert("Unable to insert email!");
alert(data);
} else {
/*$(".announcement_success").fadeIn();
$(".announcement_success").show();
$('.announcement_success').html('Announcement Successfully Added!');
$('.announcement_success').delay(5000).fadeOut(400);*/
}
},
error: function (xhr, textStatus, errorThrown) {
alert(textStatus + "|" + errorThrown);
//console.log("error"); //otherwise error if status code is other than 200.
}
});
});
});
ini_set('display_errors', 1);
error_reporting(E_ALL);
$newsletter_email = $_POST['newsletter_email'];
try {
$con = mysqli_connect("localhost", "", "", "");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$stmt = $con->prepare("INSERT INTO newsletter (email, subscribed) VALUES (?, NOW())");
if (false===$stmt) {
die('Newsletter email prepare() failed: ' . htmlspecialchars($con->error));
}
$stmt->bind_param('s', $newsletter_email);
if (false===$stmt) {
die('Newsletter email bind_param() failed: ' . htmlspecialchars($stmt->error));
}
$stmt->execute();
if (false===$stmt) {
die('Newsletter email execute() failed: ' . htmlspecialchars($stmt->error));
}
} catch(Exception $e) {
die($e->getMessage());
}
你失踪'。对一个'event'( “点击”,函数(){...'应该是'。对( “点击”,函数(事件){' – roullie
设置'dataType',并发送''相同的类型从php' – guradio
@guradio你究竟是什么意思? – Becky