2016-12-28 149 views
0

这是我views.pyURL错误,找不到网页404

from django.http import Http404 
from django.shortcuts import render 
from .models import Album 


def index(request): 
    all_albums = Album.objects.all() 
    return render(request, 'music/index.html', {'all_albums': all_albums}) 


def detail(request, album_id): 
    try: 
     album = Album.objects.get(pk=album_id) 
    except Album.DoesNotExist: 
     raise Http404("Album does not exist") 
    return render(request, '/music/detail.html', {'album': album}) 

这是我music\urls.py

from django.conf.urls import url 
from . import views 

urlpatterns = (
    url(r'^$', views.index, name='index'), 
    url(r'^(?P<album_id>[0-9]+)/$', views.detail, name='detail'), 
) 

当我运行这段代码,我得到的错误为:

error image

+0

您在浏览器中输入了哪个网址? –

+0

也添加项目的'urls.py'。 – neverwalkaloner

+0

从django.conf.urls导入包括,URL 从django.contrib中导入管理 urlpatterns的= [ URL(R '^管理员/',admin.site.urls) URL(R '^音乐/',包括('music.urls')), ] 这是项目urls –

回答

1

正如堆栈跟踪说你是@试图打开http://127.0.0.1/music/id/1页面不是http://127.0.0.1/music/1但你的urls.py没有这样的urp模式。你需要尝试打开http://127.0.0.1/music/1或添加新的模式:

url(r'^id/(?P<album_id>[0-9]+)/$', views.detail, name='detail') 

看到http://127.0.0.1/music/id/1页。