2014-11-01 79 views

回答

2

您可以递归收集孩子们在树节点的列表:

List<TreeNode> children = new List<TreeNode>(); 

foreach(TreeNode node in TV.Nodes) collectChildren(node); 

void collectChildren(TreeNode node) 
{ 
    if (node.Nodes.Count == 0) children.Add(node) 
    else foreach(TreeNode n in node.Nodes) collectChildren(n); 
} 
+0

完美,谢谢!! – 2014-11-01 10:13:55