试图验证我的形式

我试图验证我的形式在JSP中，但情况并非如此！它运行良好，但我不能调用函数validatemark这是在我的JavaScript文件试图验证我的形式

这里是我的代码：

<%@ page import = "javax.servlet.http.HttpServlet" %> 
    <%@ page language="java" contentType="text/html; charset=ISO-8859-1" 
    pageEncoding="ISO-8859-1"%> 
    <%@ page import= "org.akash.java.DabManager" %> 
    <%@ page import= "org.akash.java.GetsSets" %> 
    <%@ page import= "java.sql.ResultSet" %> 
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
    <html> 
    <head> 
    <script type="text/javascript" src="ValidateMark.js"></script> 
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
    <title>FILL IN YOUR MARKS HERE</title> 

    </head> 
    <body> 
    <form action="MarksServlet" method="post" name="SubjectMarks" onsubmit="return(validatemark());" > 

    <table cellpadding="2" width="20%" bgcolor="maroon" align="center" 
    cellspacing="2"> 

     <tr> 
      <td colspan=2> 
      <center><font size=4><b>Subject Marks Form</b></font></center> 
      </td> 
     </tr> 





    <% 
    String stid= request.getParameter("identity"); 
    %> 

    </tr> 

     <tr> 
      <td>ID</td> 
      <td><input type="text" name="iden" id="iden" size="10" value= <%=stid %>></td> 
     </tr> 





    <tr> 
     <td>Name</td> 

      <% 

      try { 

     ResultSet resu= null; 
     DabManager dab= new DabManager(); 
     resu= dab.Getsname(stid); 
     if(resu.next()) 
     { 
      String sname= resu.getString("sname");  
     %> 
     <td><input type="text" name="yourname" id="yourname" size="30" value=<%=sname %>></td> 
     <% 
     } 
     }catch(Exception e) 
     { 
      e.printStackTrace(); 
     } 
     %> 

     </tr> 

     <tr> 
      <td>Physics</td> 
      <td><input type="text" name="Physics" id="Physics" size="10"></td> 
     </tr> 

     <tr> 
      <td>Chemistry</td> 
      <td><input type="text" name="Chemistry" id="Chemistry" size="10"></td> 
     </tr> 

     <tr> 
      <td>Mathematics</td> 
      <td><input type="text" name="Maths" id="Maths" size="10"></td> 
     </tr> 

     <tr> 
      <td>Biology</td> 
      <td><input type="text" name="Biology" id="Biology" size="10"></td> 
     </tr> 

     <tr> 
      <td> 
       <input type="reset"> 
      </td> 
      <td colspan="2"> 
       <input type="submit" value="Submit Form" onclick ="confirms()"/> 
      </td> 
     </tr> 
    </table> 
</form> 

</body> 
</html>

，这里是我的ValidateMark.js javascript代码：

function validatemark() 
{ 
    if(document.SubjectMarks.iden.value == "" || isNaN(document.SubjectMarks.iden.value)) 
     { 
     alert("Please provide a valid id!"); 
     document.SubjectMarks.iden.focus() ; 
     return false; 
     } 
     if(document.SubjectMarks.yourname.value == "") 
     { 
     alert("Please provide your Name!"); 
     document.SubjectMarks.yourname.focus() ; 
     return false; 
     } 


     if(document.SubjectMarks.Physics.value == "" || isNaN(document.SubjectMarks.Physics.value)|| document.SubjectMarks.Physics.value >100) 
     { 
     alert("Please enter valid marks!!"); 
     document.SubjectMarks.Physics.focus() ; 
     return false; 
     } 

     if(document.SubjectMarks.Chemistry.value == "" || isNaN(document.SubjectMarks.Chemistry.value)|| document.SubjectMarks.Chemistry.value >100) 
     { 
     alert("Please enter valid marks!!"); 
     document.SubjectMarks.Chemistry.focus() ; 
     return false; 
     } 

     if(document.SubjectMarks.Maths.value == "" || isNaN(document.SubjectMarks.Maths.value)|| document.SubjectMarks.Maths.value >100) 
     { 
     alert("Please enter valid marks!!"); 
     document.SubjectMarks.Maths.focus() ; 
     return false; 
     } 

     if(document.SubjectMarks.Biology.value == "" || isNaN(document.SubjectMarks.Biology.value)|| document.SubjectMarks.Biology.value >100) 
     { 
     alert("Please enter valid marks!!"); 
     document.SubjectMarks.Physics.focus() ; 
     return false; 
     } 

     return true; 
} 


function confirms() 
{ 
    if(validatemark()== true) 
    alert("Marks Entered Successfully"); 
}

来源

2015-10-04 akash thadani

onsubmit="return(validatemark());"

到

onsubmit=" return validatemark();"

来源

2015-10-04 11:56:12 IamSilviu

试图验证我的形式

回答

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