Zend应用程序模块结构中的控制器类错误无效

I use Zend framework.I want to do Zend Application Module Structure 

When I open "http://localhost/aileTerapisi_z/public" I see Zend framework home page but 
When I open "http://localhost/aileTerapisi_z/public/yonetim", it give me thiss eror: 

Message: Invalid controller class ("Yonetim_IndexController") 

[h=3]Request Parameters:[/h] 
array ('module' => 'yonetim', 'controller' => 'index', 'action' => 'index',) 

how do I resolve this error 

My structure is this: 

application 
configs 
application.ini 
modules 
yonetim 
controllers 
IndexController.php 
models 
views 
helpers 
scripts 
index 
index.phtml 

default 
controllers 
IndexController.php 
models 
views 
helpers 
scripts 
index 
index.phtml 

Bootstrap.php 

library 
public 
.htaccess 
index.php 


My application/configs/application.ini file is like this: 

[production] 
phpSettings.display_startup_errors = 1 
phpSettings.display_errors = 1 
includePaths.library = APPLICATION_PATH "/../library" 
bootstrap.path = APPLICATION_PATH "/Bootstrap.php" 
bootstrap.class = "Bootstrap" 

appnamespace = "Application" 
resources.frontController.controllerDirectory = APPLICATION_PATH "/modules/default/controllers" 
resources.frontController.controllerDirectory = APPLICATION_PATH "/modules/yonetim/controllers" 
resources.frontController.params.displayExceptions = 1 

autoloadernamespaces.0 = "App_" 
autoloadernamespaces.1 = "Zend_" 
autoloadernamespaces.2 = "ZendX_" 

resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" 
resources.frontController.moduleControllerDirector yName = "controllers" 

resources.frontController.env = APPLICATION_ENV 
resources.frontController.throwerrors = false 


resources.db.adapter = PDO_Mysql 
resources.db.params.host = 
resources.db.params.username = 
resources.db.params.password = 
resources.db.params.dbname = 


;layoutpath 
resources.layout.layout = "layout" 
resources.layout.layoutPath = APPLICATION_PATH "/modules/default/views/layouts" 
resources.layout.layoutPath = APPLICATION_PATH "/modules/yonetim/views/layouts" 

[staging : production] 

[testing : production] 
phpSettings.display_startup_errors = 1 
phpSettings.display_errors = 1 

[development : production] 
phpSettings.display_startup_errors = 1 
phpSettings.display_errors = 1 
resources.frontController.params.displayExceptions = 1 
resources.frontcontroller.throwerrors = true

来源

2011-08-04 sewa

这是使用模块结构的简单application.ini。

[production] 
phpSettings.display_startup_errors = 0 
phpSettings.display_errors = 0 
includePaths.library = APPLICATION_PATH "/../library" 
bootstrap.path = APPLICATION_PATH "/Bootstrap.php" 
bootstrap.class = "Bootstrap" 
appnamespace = "Application" 
resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" 
resources.frontController.params.displayExceptions = 0 

resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts/" 
resources.layout.layout = default 

resources.modules[] = "" 
resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" 

[staging : production] 

[testing : production] 
phpSettings.display_startup_errors = 1 
phpSettings.display_errors = 1 

[development : production] 
phpSettings.display_startup_errors = 1 
phpSettings.display_errors = 1 
resources.frontController.params.displayExceptions = 1

您可以在以下文件结构中使用此配置。

application 
    configs 
    controllers 
     IndexController.php 
    layout 
     scripts 
      defalut.phtml 
      yonetim.phtml 
    models 
    modules 
     yonetim 
       controoler 
        IndexController.php 
       models 
       views 
        helpers 
        scripts 
          index 
           index.phtml  

    views 
      helpers 
       scripts 
        index 
        index.phtml 

public 
library

来源

2011-08-05 05:21:00

Zend有很好的错误控制。从错误的外观你的控制器* Yonetim_IndexController.php *确实存在，但是PHP文件里一类具有相似预期的名称：

class .*YonetimController extends Zend_Controller_Action { 
}

似乎缺少 - 其中*可以是任意的字母。如果您复制粘贴其他控制器的模板，可能会发生这种情况，并忘记更改类名。

来源

2014-04-10 11:04:18

Zend应用程序模块结构中的控制器类错误无效

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