2011-12-20 91 views
2

我有以下查询,其工作原理为MySQL:多LEFT JOIN在Access

DELETE `test1`, `test2`, `test3`, `test4` FROM 
`test1` LEFT JOIN `test2` ON test2.qid = test1.id 
LEFT JOIN test3 ON test3.tid = test2.id 
LEFT JOIN test4.qid = test1.id 
WHERE test1.id = {0} 

但它并不适用于MS访问工作。我试图在LEFT JOIN附近添加圆括号,但它在FROM子句中给我提供了语法错误。 那么这个查询应该如何看待才能在MS Access中工作?

回答

9

的访问DELETE需要一个星号(*):DELETE * FROM ...

此外,联接必须使用括号嵌套:

DELETE test1.*, test2.*, test3.*, test4.* 
FROM 
    ((test1 LEFT JOIN test2 ON test1.qid = test2.id) 
    LEFT JOIN test3 ON test2.tid = test3.id) 
    LEFT JOIN test4 ON test1.qid = test4.id 
WHERE test1.id = {0} 
+0

尽管我怀疑{0} :) – Fionnuala 2011-12-20 21:22:13

+0

噢,谢谢,我看到我错过了上次连接中的'test4 ON'部分。 – grjj3 2011-12-20 21:23:46

+0

也许他想用'String.Format(sql,some_id);'替换它,如果他使用的是C#或VB.NET。 – 2011-12-20 21:25:31

1

下面是三个表的样本select语句左联接:

SELECT 
FROM (Table1 LEFT JOIN Table2 ON Table1.field1 = Table2.field2) 
LEFT JOIN Table3 ON Table2.field2 = Table3.field3; 

您删除声明:

DELETE test1.*, test2.*, test3.*, test4.* 
FROM 
((test1 LEFT JOIN test2 ON test2.qid = test1.id) 
LEFT JOIN test3 ON test3.tid = test2.id) 
LEFT JOIN test4.qid = test1.id) 
WHERE (((test1.id) = [SomeParameter]));