处理：一个文件将写入，其他不会

我有一个奇怪的错误，我真的似乎无法找到。情况是，我有一个温度和光线传感器的arduino板：光线传感器用于查看某个房间是否“打开”（如果房间内没有移动一段时间，灯会熄灭）。我正在使用串行端口将数据推送到运行处理脚本的服务器。如果检测到的光线高于特定的阈值，arduino板推动“OPEN”，如果不是，则“CLOSED”关闭。它也推动换行的温度。它每两秒重复一次。处理：一个文件将写入，其他不会

用minicom监测串行端口，似乎所有工作正常。即使在脚本中，我输出的数据也证实一切都应该正常工作。除了当我尝试写入数据到'open.txt'似乎不是这样，而'temp.txt'工作正常（尝试尾-f两个文件，temp.txt得到更新，而open.txt只是保持为空

import processing.serial.*; 
Serial mySerial; 
PrintWriter openClosedFile; 
String openClosedFileName; 
String currentOpenClosed; 
PrintWriter temperatureFile; 
String temperatureFileName; 
int currentTemp; 

void setup() 
{ 
    mySerial = new Serial(this, Serial.list()[0], 9600); 
    openClosedFileName = "open.txt"; 
    openClosedFile = createWriter(openClosedFileName); 
    currentOpenClosed = "CLOSED"; 
    temperatureFileName = "temp.txt"; 
    temperatureFile = createWriter(temperatureFileName); 
    currentTemp = 0; 
} 

void draw() 
{ 
    if (mySerial.available() > 0) 
    { 
     String value = mySerial.readStringUntil('\n'); 
     if (value != null) 
     { 
      String timestamp = nf(day(),2) + "/" + nf(month(), 2) + "/" + year() + " " +   nf(hour(),2) + ":" + nf(minute(),2) + ":" + nf(second(),2); 
     println(timestamp); 
     value = trim(value); 
      if (isNumeral(value)) 
      writeTemperature(value); 
      else 
      writeOpenClosed(value); 
     } 
    } 
} 

void writeOpenClosed(String val) 
{ 
    print("OpenClosed: "); 
    println(val); 
    boolean writtenToFile = false; 
    openClosedFile = createWriter(openClosedFileName); 
    if (val.equals("OPEN") && !currentOpenClosed.equals("OPEN")) 
    { 
    println("val=OPEN and currentOpenClosed!=OPEN"); 
    openClosedFile.print("1"); 
    writtenToFile = true; 
    } 
    else if (val.equals("CLOSED") && !currentOpenClosed.equals("CLOSED")) 
    { 
    println("val=CLOSED and currentOpenClosed!=CLOSED"); 
    openClosedFile.print("0"); 
    writtenToFile = true; 
    } 

    if (writtenToFile) 
    { 
    currentOpenClosed = val; 
    openClosedFile.flush(); 
    openClosedFile.close(); 
    println("Written OpenClosed To File"); 
    } 
} 

void writeTemperature(String val) 
{ 
    print("temperature: "); 
    println(val); 
    int intTemp = Integer.parseInt(val); 
    if (intTemp != currentTemp) 
    { 
    currentTemp = intTemp; 
    temperatureFile = createWriter(temperatureFileName); 
    temperatureFile.print(val); 
    temperatureFile.flush(); 
    temperatureFile.close(); 
    println("Written Temperature To File"); 
    } 
} 

boolean isNumeral(String val) 
{ 
    for (int i = 0; i < val.length(); i++) 
    { 
    if (val.charAt(i) < 48 || val.charAt(i) > 57) 
     return false; 
    } 
    return true; 
}

我认为会有一些语法错误（我以前没有使用过处理），但两者的功能似乎是在做同样的...

一些示例输出：

Listening for transport dt_socket at address: 8212 

30/10/2014 12:14:57 
OpenClosed: CD 
30/10/2014 12:14:57 
temperature: 24 
Written Temperature To File 
30/10/2014 12:14:59 
OpenClosed: CLOSED 
30/10/2014 12:14:59 
temperature: 25 
Written Temperature To File 
30/10/2014 12:15:01 
OpenClosed: CLOSED 
30/10/2014 12:15:01 
temperature: 24 
Written Temperature To File 
30/10/2014 12:15:03 
OpenClosed: CLOSED 
30/10/2014 12:15:03 
temperature: 25 
Written Temperature To File 
30/10/2014 12:15:05 
OpenClosed: OPEN 
val=OPEN and currentOpenClosed!=OPEN 
Written OpenClosed To File 
30/10/2014 12:15:05 
temperature: 20 
Written Temperature To File 
30/10/2014 12:15:07 
OpenClosed: OPEN 
30/10/2014 12:15:07 
temperature: 20 
30/10/2014 12:15:09 
OpenClosed: OPEN 
30/10/2014 12:15:09 
temperature: 20 
^C

我没有看到什么，或者可能会发生什么吗？

来源

2014-10-30 Jelco Adamczyk

好吧，我想我明白了，实际上我是愚蠢的。

对于最终未来的读者：打电话

openClosedFile = createWriter(openClosedFileName);

在writeOpenClosed（）函数

将打开该文件，如果没有已被写入它永远不会关闭。由于该文件永远不会被关闭（因为下次调用该函数时会有一个新对象），所以它不会释放要读取的文件。

来源

2014-10-30 15:46:58

处理：一个文件将写入，其他不会

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