获取类型错误：列表索引必须是整数，而不是元组

Question

我想实现的算法，但要得到一个错误，我不知道是什么原因：

size = len(data) 
total = sum(data) 

barray = [[False for x in range(int(size+1))] for x in range(int((total/2)+1))] 

for x in range(0,size): 
    barray[0][x] = True 

for x in range(1,int(total/2)): 
    barray[x][0] = True 

for i in range(1,int(total/2)): 
    for j in range(1,size): 
     barray[i,j] = (barray[i, j - 1] or barray[i - data[j - 1], j - 1]) if data[j-1] <= i else barray[i, j - 1] 

return barray[int(total/2),size] 

错误：

Traceback (most recent call last): 
File "C:/Users/tuf21741/PycharmProjects/PyBackup/test.py", line 25, in <module> 
assert checkio([10, 10]) == 0, "1st example" 
File "C:/Users/tuf21741/PycharmProjects/PyBackup/test.py", line 17, in checkio 
barray[i,j] = (barray[i, j - 1] or barray[i - data[j - 1], j - 1]) if data[j-1] <= i else barray[i, j - 1] 
TypeError: list indices must be integers, not tuple 

Answer 1

barray[i,j] = (barray[i, j - 1] or barray[i - data[j - 1], j - 1]) if data[j-1] <= i else barray[i, j - 1] 

看起来你应该在这里为你的索引使用单独的方括号。

barray[i][j] = (barray[i][j - 1] or barray[i - data[j - 1]][j - 1]) if data[j-1] <= i else barray[i][j - 1] 

并且对于return语句也是如此。

return barray[int(total/2)][size]