2017-04-26 269 views
-4

我正在创建一个队列程序的Java数组来代表医生阵列中的病人。它可以让我在数据结构中添加节点,但是当我尝试打印出来时,它会炸毁我。这里是方法Java队列仅打印for循环中的最后一个元素。

static boolean [] openflag = new boolean[6]; 
static queue [] Clinic = new queue[6]; 
static String [] Doctor = {"Doctor 1", Doctor 2", "Doctor 3","Doctor 
4","Doctor 5","Doctor 6"}; 
final static String HEADING = "The clinic moniter of Dylan Rychlik"; 
static int MAX = 6; 
    public static void Listpaitents() 
    { 
    int queuechoice; 
JOptionPane.showMessageDialog(null, "Which doctor would you like to print?"); 
String InputString = JOptionPane.showInputDialog(null,Doctor, HEADING, 
JOptionPane.QUESTION_MESSAGE); 

queuechoice = Integer.parseInt(InputString); 
if (openflag[queuechoice -1 ] == false){ 
    JOptionPane.showMessageDialog(null, "Sorry, that doctor is notaviable"); 
    } 
else{ 
    Paitent[] array = Clinic[queuechoice -1].toArray(); 
    //int size = Clinic[queuechoice -1].getSize(); 
    int limit = Clinic[queuechoice -1].getSize(); 
    //System.out.println(limit); 
    int x; String out = " Members of the list are: \n"; 
    // boolean exit = false; 
    for(x = 1; x <= limit; x++) { 
    out += array[x-1].Print() + "\n"; 
    // System.out.println(array[x-1] + "\n"); 
    } 
    JOptionPane.showMessageDialog(null,out); 
    } 
} 

这里是队列类中的toarray()方法。

public static Paitent[] toArray() 
{ 
    int x = Length; 
    Paitent[] Array = new Paitent[Length]; 
    queuenode Current = rear; 
    for (x = Length; ((Current != null) && (x >= 1));x--) 
    { 
     Array[x-1] = new Paitent(); 
     Array[x-1].update(Current.info); 
     Current = Current.next; 

    } 
    return Array; 

    } 

最后,这里是paitent类

public class Paitent { 
protected static String name; 
protected static String telephone; 
protected static int ID; 
//Creates a constructor for a paitent object 
public void paitent() 
{ 

name = ""; 
telephone = " "; 
ID = 0; 

    } 
//updates the country object 
public void update(Paitent thisThing) 
{ 

name = thisThing.name; 
telephone = thisThing.telephone; 
ID = thisThing.ID; 
} 
//asks for user input for country objects 
public void input(int i) 
    { 
String PatronHeading = "Country Data Entry"; 
String entername; 

int enterID; 
String enterphone; 


entername = JOptionPane.showInputDialog(null, "Please Enter the name of 
paitent #" + i +": ", PatronHeading, JOptionPane.QUESTION_MESSAGE); 

enterphone = JOptionPane.showInputDialog(null, "Please Enter the telephone 
number for paitent #" + i +": ", PatronHeading, 
JOptionPane.QUESTION_MESSAGE); 
String PNumberString = JOptionPane.showInputDialog(null, "Please Enter the 
ID for paitent #" + i +": ", PatronHeading, JOptionPane.QUESTION_MESSAGE); 
enterID = Integer.parseInt(PNumberString); 



name = entername; 

telephone = enterphone; 
ID = enterID; 
} 




//prints the results 
public String Print() 
{ 
String outputString; 
outputString = "Paitent: " + "-" + name + "\n" + " Telephone number " + 
telephone + " ID " + ID; 
return outputString; 
} 
//gets and sets the PCI in order to sort them 
    } 

任何帮助吗?尝试了几种策略来解决它,似乎没有任何工作。有很多代码,所以如果你需要完整的代码,请让我知道!

+2

'它me'和'炸毁似乎没有任何工作可以完全解决问题。创建一个[mcve]。 – Idos

+3

有两个主要的问题使得这个问题变得很恐怖:你的代码的格式不够理想,另外你应该遵循'java命名约定',因为这增加了混乱的格式。 – SomeJavaGuy

+1

Aslo你提供的代码不能编译。第一个编译错误将在这里:'{“Doctor 1”,Doctor 2“,”Doctor 3“,”Doctor 4“,”Doctor 5“,”Doctor 6“};' – Jens

回答

0

您的代码存在的问题是您正在使用static变量。这意味着他们永远只能有一个值

所以更改

protected static String name; 
protected static String telephone; 
protected static int ID; 

protected String name; 
protected String telephone; 
protected int ID; 

编辑和清理你的代码

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