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我想从我的数据库中检索数据,我写了这个代码如何在Android应用程序中将从MySQL检索到的数据插入到数组中?
<?php
require "conn.php";
$mysql_qry = "select * from domande";
$res = mysqli_query($conn,$mysql_qry);
$result = array();
while($row = mysqli_fetch_array($res)){
array_push($result,
array('id_domanda'=>$row[0],
'domanda'=>$row[1],
'username'=>$row[2]
));
}
echo json_encode(array("result"=>$result));
mysqli_close($conn);
?>
应该返回数组。我已经能够显示一个警告对话框数组中这样说:
class BackgroundWorkerDomande extends AsyncTask<String,Void,String> {
Context context;
AlertDialog alertDialog;
BackgroundWorkerDomande (Context ctx){
context = ctx;
}
@Override
protected String doInBackground(String... params) {
String type = params[0];
if (type=="getquestion"){
try {
URL url = new URL(params[3]);
HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
httpURLConnection.setDoInput(true);
InputStream inputStream = httpURLConnection.getInputStream();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"));
String result = "";
String line = "";
while ((line = bufferedReader.readLine()) != null) {
result += line;
}
bufferedReader.close();
inputStream.close();
httpURLConnection.disconnect();
return result;
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
@Override
protected void onPreExecute() {
alertDialog = new AlertDialog.Builder(context).create();
alertDialog.setTitle("Status");
}
@Override
protected void onPostExecute(String result) {
alertDialog.setMessage(result);
alertDialog.show();
}
@Override
protected void onProgressUpdate(Void... values) {
super.onProgressUpdate(values);
}
}
,但如果我想插入的结果在我的MainActivity宣布一个新的阵列我应该怎么办?我只是在互联网上遵循一些教程来编写这段代码,所以我不完全知道它是如何工作的。 (对不起,我的英文不好)