我想在进程之间进行同步。我的计算机有2个核心。用户可以从命令行输入模拟编号。如果输入大于2,则第3次休息进程必须等待其中一个进程完成。如果其中一个完成,则应执行下一个进程。例如,前两个进程已经在进行,并假设第1个进程在第2个进程之前完成。现在第3个进程应该被执行。我是bash新手,我想通了。可以看到anywait:command not found。我该怎么做?这里是我的脚本:等待一个进程完成并执行另一个进程
#!/bin/bash
# My first script
count=2
echo -n "Please enter the number of simulation :"
read number
echo "Please enter the algorithm type "
printf "0 for NNA\n1 for SPA\n2 for EEEA :"
while read type; do
case $type in
0) cd /home/cea/Desktop/simulation/wsnfuture
taskset -c 0 ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/NNA/NNA0/0 &
taskset -c 1 ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/NNA/NNA0/1 &
while [ $count -lt $number ]; do
anywait
cd /home/cea/Desktop/simulation/wsnfuture
mkdir /home/cea/Desktop/simulation/RESULTS/NNA/NNA$count
taskset -c $((count % 2)) ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/NNA/NNA$count/$count &
count=$((count + 1))
done
;;
1) while [ $count -lt $number ]; do
cd /home/cea/Desktop/simulation/wsnfuture1
taskset -c $((count % 2)) ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/SPA/$count &
count=$((count + 1))
done
;;
2) while [ $count -lt $number ]; do
cd /home/cea/Desktop/simulation/wsnfuture2
taskset -c $((count % 2)) ./wsnfuture -u Cmdenv omnetpp.ini > /home/cea/Desktop/simulation/RESULTS/EEEA/$count &
count=$((count + 1))
done
;;
*) echo "You did not enter a number"
echo "between 0 and 2."
echo "Please enter the algorithm type "
printf "0 for NNA\n1 for SPA\n2 for EEEA :"
esac
done
function anywait(){
while ps axg | grep -v grep | grep wsnfuture> /dev/null; do sleep 1; done
}
你能解决你的问题,在我的答案中使用'wait'命令? – Inian
你可以使用select statings来获得用户响应,等待等待,如果你仍然需要ps,那么pgrep会更好。 – SaintHax