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所以我试图创建一个简单的iOS程序,我可以将聊天消息保存到远程MySQL服务器,然后加载它。如何发送“聊天消息”从iOS TextField到远程数据库
我的应用程序有文本框,我可以输入数据和一个按钮将数据保存到外部数据库。
我的PHP文件看起来像这样:
<?php
$DB_HostName = "hostname";
$DB_Name = "dbname";
$DB_User = "dbuser";
$DB_Pass = "dbpass";
$DB_Table = "dbtable";
if (isset ($_GET["name"]))
$name = $_GET["name"];
else
//$name = "Ghalia";
echo ('Please enter a name');
$con = mysql_connect($DB_HostName,$DB_User,$DB_Pass) or die(mysql_error());
mysql_select_db($DB_Name,$con) or die(mysql_error());
$sql = "insert into $DB_Table (name) values('$name');";
$res = mysql_query($sql,$con) or die(mysql_error());
mysql_close($con);
if ($res) {
echo "success";
}else{
echo "faild";
}
?>
我ViewController.h文件看起来像这样:
#import "ViewController.h"
@interface ViewController()
@end
@implementation ViewController
@synthesize txtName;
- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
}
- (void)didReceiveMemoryWarning {
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
- (IBAction)insert:(id)sender {
//create string contains url address for php file, the file name is phpfile.php, it receives a parameter :name
NSString *strURL = [NSString stringWithFormat:@"http://xxdsadxx.net/phpFile.php?name=%@", txtName.text];
//to execute php code
NSData *dataURL = [NSData dataWithContentsOfURL:[NSURL URLWithString:strURL]];
//to receive the returned value
NSString *strResult = [[NSString alloc] initWithData:dataURL encoding:NSUTF8StringEncoding];
NSLog(@"%@", strResult);
}
@end
现在,我把它编码为唯一商店名称。
我想存储像“你好,你好吗?”的聊天消息,该字符串将不会正确存储到外部服务器。任何想法如何我可以实现这一目标?谢谢。
您是说发送名称的代码无法正常工作,并且您希望在继续发送聊天文本之前完成这项工作? – 2014-11-22 22:13:54
此代码适用于名称输入。但我想让它识别多个字符串,例如“你好吗?”。我怎么做? – 2014-11-23 21:25:27