加密/解密矢量<string>

Question

我一直在个人序列化过程中工作，但我坚持在保存/加载后取回解密的向量。它可以很好地保存和加载数据，但矢量库存会在转换中丢失它的定义，所以我必须重新制作它，这会在程序中稍后使用它。下面的代码片段显示了我如何加密/解密。

struct bin{ 
    map<string, int>::iterator it; 
    int modify_string; 
    vector<string> uncrypt_vec; 
    map<string, int> encryption; 
    void set_up_code(){ 
     string alphabet[] = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"}; 
     int letter_num=1; 
     for(int i = 0; i < 27; ++i){ 
      string letter = alphabet[i]; //Assign each letter to a number 
      encryption.insert(pair<string,int>(letter,letter_num)); 
      letter_num++; 
     } 
     encryption.insert(pair<string,int>(" ", -1)); 
    } 
    int encrypt_vector(vector<string>& crypt){ 
     stringstream ssv; 
     for(unsigned int i = 0; i < crypt.size(); ++i){ 
      string word = crypt[i]; //Grab each string 
      int mod_word[word.size()]; 
      for(unsigned int x = 0; x < word.size(); ++x){ 
       stringstream ssl; 
       string letter; 
       char let = word[x]; //Convert each letter of the string into an integer 
       ssl << let; 
       ssl >> letter; 
       int num = encryption[letter]; 
       mod_word[x] = num; 
      } 
      mod_word[word.size()] = 0; //Include a zero for each word 
      copy(mod_word, mod_word+word.size()+1, ostream_iterator<int>(ssv)); 
     } 
     ssv >> modify_string; //Put into int modify_string and return 
     return modify_string; 
    } 
    vector<string> decrypt_vector(int& uncrypt){ 
     string num; 
     stringstream ssn; 
     ssn << uncrypt; //Store the numbers in a string 
     ssn >> num; 
     string mod_word; 
     string word; 
     for(unsigned int i=0;i<num.size();++i){ 
      int number; 
      char check_num = num[i]; 
      stringstream ssctn; 
      ssctn << check_num; //Kinda stupid way of doing it 
      ssctn >> number; //Pulls int from num[i], then checks it against 0 
      if(number==0){ //If break point 
       uncrypt_vec.push_back(mod_word); //Push back the word 
       mod_word.clear(); 
      } 
      int letter; 
      stringstream sscn; 
      char let = num[i]; 
      sscn << let; //Pull each letter from uncrypt, change back to letter based on encryption 
      sscn >> letter; 
      for(it = encryption.begin(); it != encryption.end(); ++it){ 
       if(it->second == letter){ 
        mod_word.append(it->first); 
        break; 
       } 
      } 
     } 
     cout << "Done" << endl; 
     return uncrypt_vec; 
    } 
}binary; 

struct player{ 
    vector<string> inventory; 
    int inventory_en; //en for encrypted 
    void save(){ 
     inventory_en = binary.encrypt_vector(inventory); 
    } 

    void load(){ 
     vector<string> inventory; //Must recreate, type is lost otherwise, crashes 
     inventory = binary.decrypt_vector(inventory_en); 
     vector<string>::iterator i; 
     for(i=inventory.begin();i!=inventory.end();++i){ 
      cout << *i << endl; //Prints correctly here 
     } 
    } 
}character; 

int main(){ 
    character.inventory.push_back("abc"); 
    character.inventory.push_back("edf"); 
    binary.set_up_code(); 
    character.save(); 
    character.load(); 
} 

当我尝试打印出character.inventory后，它崩溃。如果我没有在character.load（）函数中将character.inventory定义为字符串，它也会崩溃。那么我如何才能将character.inventory定义为一个向量，我可以稍后在程序中调用（从结构体）？

我使用output_file.write((char*)&structObj, sizeof(structObj));将数据写入文件，并以相同的方式读取（因此需要加密/解密，不能以这种方式保存字符串）。

请不要指示我去图书馆为我做。

Answer 1

您索引字母[26]，但最后的有效指标为25。

for(int i = 0; i < 27; ++i){ 
     string letter = alphabet[i];