MATLAB简化循环

Question

好吧，所以我正在努力与这一个。下面的代码适用于我需要的方式，但是，我确信它可以更短，更简单。我知道我可以使用for循环来缩短它，我只是不知道怎么做，任何人都可以在正确的方向指向我。谢谢:)

如果它不是明确的形式代码我想要做的。我想单独卷积信号和房间脉冲响应一起使用比卷积功能

close all; 
clear all; 

[x Fs] = wavread('bass.wav'); 
[x2] = wavread('drums.wav'); 
[x3] = wavread('bongo.wav'); 
[x4] = wavread('shaker.wav'); 
[x5] = wavread('gtr.wav'); 

hrir = wavread('HRIR_RR.wav'); 
hrir2 = wavread('HRIR_RL.wav'); 
hrir3 = wavread('HRIR_FR.wav'); 
hrir4 = wavread('HRIR_FL.wav'); 
hrir5 = wavread('HRIR_C.wav'); 

hrir_L = hrir(:,1); 
hrir_R = hrir(:,2); 

hrir_L2 = hrir2(:,1); 
hrir_R2 = hrir2(:,2); 

hrir_L3 = hrir3(:,1); 
hrir_R3 = hrir3(:,2); 

hrir_L4 = hrir4(:,1); 
hrir_R4 = hrir4(:,2); 

hrir_L5 = hrir5(:,1); 
hrir_R5 = hrir5(:,2); 

L = length(x) + length(hrir) -1; % Output data length 
X = fft([x ; zeros(length(hrir_L),1)]); 
HL = fft([hrir_L ; zeros(length(x),1)]); 
HR = fft([hrir_R ; zeros(length(x),1)]); 

L2 = length(x2) + length(hrir2) -1; % Output data length 
X2 = fft([x2 ; zeros(length(hrir_L2),1)]); 
HL2 = fft([hrir_L2 ; zeros(length(x2),1)]); 
HR2 = fft([hrir_R2 ; zeros(length(x2),1)]); 

L3 = length(x3) + length(hrir3) -1; % Output data length 
X3 = fft([x3 ; zeros(length(hrir_L3),1)]); 
HL3 = fft([hrir_L3 ; zeros(length(x3),1)]); 
HR3 = fft([hrir_R3 ; zeros(length(x3),1)]); 

L4 = length(x4) + length(hrir4) -1; % Output data length 
X4 = fft([x4 ; zeros(length(hrir_L4),1)]); 
HL4 = fft([hrir_L4 ; zeros(length(x4),1)]); 
HR4 = fft([hrir_R4 ; zeros(length(x4),1)]); 

L5 = length(x5) + length(hrir5) -1; % Output data length 
X5 = fft([x5 ; zeros(length(hrir_L5),1)]); 
HL5 = fft([hrir_L5 ; zeros(length(x5),1)]); 
HR5 = fft([hrir_R5 ; zeros(length(x5),1)]); 

out_L = zeros(L,1); % output buffer 
out_R = zeros(L,2); 

out_L2 = zeros(L2,1); % output buffer 
out_R2 = zeros(L2,2); 

out_L3 = zeros(L3,1); % output buffer 
out_R3 = zeros(L3,2); 

out_L4 = zeros(L4,1); % output buffer 
out_R4 = zeros(L4,2); 

out_L5 = zeros(L5,1); % output buffer 
out_R5 = zeros(L5,2); 


out_L = ifft(X .* HL); % multiplication of fft results & ifft 
out_R = ifft(X .* HR); 

out_L2 = ifft(X2 .* HL2); % multiplication of fft results & ifft 
out_R2 = ifft(X2 .* HR2); 

out_L3 = ifft(X3 .* HL3); % multiplication of fft results & ifft 
out_R3 = ifft(X3 .* HR3); 

out_L4 = ifft(X4 .* HL4); % multiplication of fft results & ifft 
out_R4 = ifft(X4 .* HR4); 

out_L5 = ifft(X5 .* HL5); % multiplication of fft results & ifft 
out_R5 = ifft(X5 .* HR5); 

out_L = out_L + out_L2 + out_L3 + out_L4 + out_L5; 
out_R = out_R + out_R2 + out_R3 + out_R4 + out_R5; 

out = [out_L out_R]; 

sound(out, Fs) 

Answer 1

你可以尝试使用电池阵列等不同的工艺。这些是所有类型数据的通用容器：

fn = {'a.wav','b.wav','c.wav'} 

for i=1:length(fn) 
    h{i} = wavread(fn{i}) 

    hrir_L{i} = h{i}(:,1); 
    hrir_R{i} = h{i}(:,2); 

    .... 

end