检查和替换文件夹和子文件夹中的文本

Question

我试图通过文件夹和子文件夹来查找包含此短语的文本文件中的短语“测试程序”，并将其替换为“测试此程序”。我也试图显示子文件夹的内容。我可以显示父文件夹的内容，但不能显示子文件夹。我也可以编辑第一个文件（Test.txt）的文本，但我想通过搜索父文件夹（Test）而不是访问此文件来编辑第二个文件（Test1.txt）中的文本直接文件。任何有关如何搜索和编辑文件夹/子文件夹中的特定文本的建议将不胜感激。

File f = new File("C:/Test/Test.txt"); 

    FileInputStream fs = null; 
    InputStreamReader in = null; 
    BufferedReader br = null; 

    StringBuffer sb = new StringBuffer(); 
    try 
    { 
     fs = new FileInputStream(f); 
     in = new InputStreamReader(fs); 
     br = new BufferedReader(in); 
     for (;;) 
     { 
     String textinLine = br.readLine(); 
     if (textinLine == null) { 
      break; 
     } 
     sb.append(textinLine); 
     } 
     String textToEdit1 = "hello"; 
     int cnt1 = sb.indexOf(textToEdit1); 
     sb.replace(cnt1, cnt1 + textToEdit1.length(), "hello there"); 


     fs.close(); 
     in.close(); 
     br.close(); 
    } 
    catch (FileNotFoundException e) 
    { 
     e.printStackTrace(); 
    } 
    catch (IOException e) 
    { 
     e.printStackTrace(); 
    } 
    try 
    { 
     FileWriter fstream = new FileWriter(f); 
     BufferedWriter outobj = new BufferedWriter(fstream); 
     outobj.write(sb.toString()); 
     outobj.close(); 
    } 
    catch (Exception e) 
    { 
     System.err.println("Error: " + e.getMessage()); 
    } 

//搜索文件夹中的文/子

File f1 = new File("C:/Test/Test1/Test1.txt"); 

    FileInputStream fs1 = null; 
    InputStreamReader in1 = null; 
    BufferedReader br1 = null; 

    StringBuffer sb1 = new StringBuffer(); 
    try 
    { 
    fs1 = new FileInputStream(f1); 
     in1 = new InputStreamReader(fs1); 
     br1 = new BufferedReader(in1); 
     for (;;) 
     { 
     String textinLine1 = br1.readLine(); 
     if (textinLine1 == null) { 
      break; 
     } 
     sb1.append(textinLine1); 
     String checkWords = "run away"; 
     boolean retVal = textinLine1.contains(checkWords); 
     } 

     String textToEdit11 = "test program"; 
     int cnt11 = sb1.indexOf(textToEdit11); 
     sb1.replace(cnt11, cnt11 + textToEdit11.length(), "test this program"); 

     fs1.close(); 
     in1.close(); 
     br1.close(); 
    } 
    catch (FileNotFoundException e1) 
    { 
     e1.printStackTrace(); 
    } 
    catch (IOException e1) 
    { 
     e1.printStackTrace(); 
    } 
    try 
    { 
     FileWriter fstream1 = new FileWriter(f1); 
     BufferedWriter outobj1 = new BufferedWriter(fstream1); 
     outobj1.write(sb1.toString()); 
     outobj1.close(); 
    } 
    catch (Exception e1) 
    { 
     System.err.println("Error: " + e1.getMessage()); 
    } 
    File folder1 = new File("C:\\"); 
    File[] filesInDir = folder1.listFiles(); 

    String dirname = "C:\\Test"; 
    File f2 = new File(dirname); 
    if (f2.isDirectory()) 
    { 
     System.out.println("Directory of " + dirname); 
     String[] sR = f2.list(); 
     for (int iR = 0; iR < sR.length; iR++) 
     { 
     File f2R = new File(dirname + "/" + sR[iR]); 
     if (f2R.isDirectory()) { 
      System.out.println(sR[iR] + " is a directory"); 
     } else { 
      System.out.println(sR[iR] + " is a file"); 
     } 
     } 
    } 
    else 
    { 
     System.out.println(dirname + " is not a directory"); 
    }" 

Answer 1

假设你使用Java 7或更高版本。

请参阅The Java™ Tutorials, Walking the File Tree。

我也会使用try-with-resources流，读者和作家。