2012-02-28 70 views
0

您好我有一个过程,像这样:TSQL - 聚合函数表达式上含集合错误

CREATE PROCEDURE dbo.DWS_PROG (
           @fromDate datetime = '2012-01-01', 
           @maxMoney money = 200, 
           @limit int = 200 
          ) 
AS 
SET NOCOUNT ON; 

SELECT TOP (@limit) 
    convert(int,P.P_ID) AS 'ID' 
    , max(convert(MONEY,isnull(P.NGp,P.NGz))) AS 'NG' 
    , max(convert(MONEY,(CASE WHEN D.Doc_Type = 0x0000000000000016 
           THEN Cash_PLN 
           ELSE 0 END))) AS 'Interests' 
    , (SELECT TOP 1 convert(VARCHAR, H.Data_zmiany,105) 
     FROM dbo.Pozew_Historia_Stanow H 
     WHERE H.P_ID = P.P_ID 
      AND H.Stan_nastepny_id = 0x000000000000000D /*PZ*/) AS 'Data Pozwu' 
    , max((CASE WHEN Sad_Id=0x0000000000000E08 
       THEN 'EL' 
       ELSE 'PA' END)) AS 'TYPE' 
    , max((CASE WHEN Cost_Name =0x0000000000000008 
       THEN convert(varchar, Pay_Date,105) 
       ELSE NULL END)) AS 'Data pierwszego kosztu wpisu sądowego' 
    , (SELECT TOP 1 convert(VARCHAR, H.Data_zmiany,105) 
     FROM dbo.Pozew_Historia_Stanow H 
     WHERE H.P_ID = P.P_ID 
      AND H.Stan_nastepny_id = 0x00000000000000DD /*EGZ-1*/) AS 'Data wszczęcia egzekucji' 
    , sum((CASE WHEN D.Doc_Type = 0x0000000000000003 
       AND D.Pay_Date >= @fromDate 
       AND D.Pay_Date < DATEADD(mm,DATEDIFF(mm,0,@fromDate) + 1,0) 
       THEN Cash_PLN 
       ELSE 0 END)) AS 'M0' 
FROM dbo.Pozew P 
JOIN dbo.Orders Z 
    ON Z.Orders_Id = P.Orders_Id 
JOIN dbo.Docs D 
    ON D.P_ID = P.P_ID 
WHERE ((P.NGp IS NOT NULL AND P.NGp < @maxMoney) OR (P.NGp IS NULL AND P.NGz < @maxMoney)) 
    AND P.Stan IN ('PZ-PORAŻKA','PZ-PORAŻ-UB','PZ-PSPPOR-SP','PZ-PSPPOR-UP','PZ-PSSSUK-UP','PZ-ZAPŁATA','EGZ-C-ROSZ-1','EGZ-C-ROSZ-2','EGZ-SUKCES-S','EGZ-ZAS-R','EGZ-NZAS-R','EGZ-BS-1C','EGZ-WSZP-1','EGZ-WSZP-2','EGZ-SPL') 
    AND (SELECT TOP 1 dbo.Docs.Pay_Date 
     FROM dbo.Docs 
     WHERE dbo.Docs.P_ID = P.P_ID 
      AND dbo.Docs.Cost_Name = 0x0000000000000008 
    ORDER BY dbo.Docs.Pay_Date) >= @fromDate 
GROUP BY P.P_ID 

这basicly工作正常,但我有一个错误。 在JOIN之前的最后一行中,我为所有类型为0x00 ... 03的文档和Pay_date介于@param和param之间的月末之间进行结算。简单和工程:)

但我必须与子查询替换@fromDate:

SELECT TOP 1 dbo.Docs.Pay_Date 
    FROM dbo.Docs 
WHERE dbo.Docs.P_ID = P.P_ID 
    AND dbo.Docs.Cost_Name = 0x0000000000000008 
    AND dbo.Docs.Pay_Date >= @fromDate 
ORDER BY dbo.Docs.Pay_Date 

所以,对于每一个文件的查询会第一时间与日期特定类型的付款,然后将总结从开始的所有款项这个日期到月底。

SUM应该是这样的:

SUM((CASE WHEN D.Doc_Type = 0x0000000000000003 
      AND D.Pay_Date >= 
       (SELECT TOP 1 dbo.Docs.Pay_Date 
        FROM dbo.Docs 
       WHERE dbo.Docs.P_ID = P.P_ID 
        AND dbo.Docs.Cost_Name = 0x0000000000000008 
        AND dbo.Docs.Pay_Date >= @fromDate 
       ORDER BY dbo.Docs.Pay_Date) 

      AND D.Pay_Date < DATEADD(mm, DATEDIFF(mm, 0, 
       (SELECT TOP 1 dbo.Docs.Pay_Date 
       FROM dbo.Docs 
       WHERE dbo.Docs.P_ID = P.P_ID 
        AND dbo.Docs.Cost_Name = 0x0000000000000008 
        AND dbo.Docs.Pay_Date >= @fromDate 
       ORDER BY dbo.Docs.Pay_Date)) + 1,0) 
     THEN Cash_PLN 
     ELSE 0 END)) AS 'M0' 

但这样做Management Studio中抛出一个错误后:

Cannot perform an aggregate function on an expression containing an aggregate or a subquery.

我试图解决近2天。 任何想法?

对不起,不显示表的结构,但数据库是太大了,我只需要一种方法来解决这个错误:)

我的表看起来像这样: 表Pozew:ID,姓名等

表文档:文档ID,p_id的(从Pozew表键),DOC_TYPE,cost_name,pay_date,cash_PLN

而且样本记录看起来像这样:

文档:

1,1,15,8,'2011-02-04',400
1,1,3,5,'2011-02-09',0
1,1,3,5,'2011 -02-12' ,0
1,1,3,5, '2011-02-04',0

简单的场景: 我们添加一条记录到文件表说,我们有cost_name 1号文件= 0x8,则添加其他文档,但Doc_Type = 0x3。

所以我们想要得到所有具有doc_Type = 0x3的文档,并且在cost_name = 0x8的第一个文档的创建日期和月末之间添加。 但是我们必须将他们分组为每个Pozew_id。

对不起,我倒英语:/

我创建了一个简单的查询,将更加清楚地显示我的问题:

DECLARE @fromDate varchar 
SET @fromDate = '2011-06-01' 
SELECT TOP 100 
sum((CASE WHEN D.Typ_dokumentu = 0x0000000000000003 
      AND D.Data_platnosci >= 
      (SELECT TOP 1 Data_platnosci 
      FROM Dokumenty 
      WHERE Pozew_Id = P.Pozew_Id 
      AND Nazwa_kosztu = 0x0000000000000008 
      AND Data_platnosci >= @fromDate 
      GROUP BY Pozew_Id) 
      AND Data_platnosci < DATEADD(mm,DATEDIFF(mm,0, 
      (SELECT TOP 1 Data_platnosci 
      FROM Dokumenty 
      WHERE Pozew_Id = P.Pozew_Id 
      AND Nazwa_kosztu = 0x0000000000000008 
      AND Data_platnosci >= @fromDate 
      GROUP BY Pozew_Id) 
      ) + 1,0) THEN Kwota_PLN ELSE 0 END)) AS 'M0' 
FROM 
Dokumenty D 
JOIN Pozew P 
    ON D.Pozew_Id = P.Pozew_Id 
WHERE 
((P.NGp IS NOT NULL 
AND 
P.NGp < 200) 
OR 
(P.NGp IS NULL 
AND 
P.NGz < 200)) 
AND 
P.Stan IN ('PZ-PORAŻKA','PZ-PORAŻ-UB','PZ-PSPPOR-SP') 
AND 
(SELECT TOP 1 
    dbo.Dokumenty.Data_platnosci 
FROM 
    dbo.Dokumenty 
WHERE 
    dbo.Dokumenty.Pozew_Id = P.Pozew_Id 
    AND 
    dbo.Dokumenty.Nazwa_kosztu = 0x0000000000000008 
ORDER BY 
    dbo.Dokumenty.Data_platnosci) >= @fromDate 
+0

对不起@Filip德沃思与格式混乱:/ – Misiu 2012-02-28 09:55:17

+0

不用担心。在vg中gg = G。 – 2012-02-28 09:58:15

回答

0

岂不是可能有一个派生表在你的加盟商提供“第一每种类型的支付@fromDate后”,然后在你的选择声明与此相比较。

即衍生查询类似

select p_id, min(pay_date) startDate 
from docs 
where cost_name = 0x0000000000000008 
    and pay_date >= @fromDate 
group by p_id 
order by pay_date 

您按付款从而获得相应的起始日期的加盟派生表。

那么你的总和:

sum((case when d.doc_type = 0x0000000000000003 
      and d.pay_date >= startDate 
      and month(d.pay_date) = month(startDate) 
      and year(d.pay_date) = year(startDate)) then cash_pln 
      else 0 end) as 'M0' 

注意我没有尝试这样做,因此它可能不会是完全正确的,但希望它显示的原则

+0

我已经完成了另一个包含来自您的查询的记录的表的联接。它像一个魅力:) – Misiu 2012-02-29 11:03:39

+0

伪SQL是前进的方向!谢谢 – kaj 2012-02-29 11:53:47

0

我会把pay_date到一个变量,并与工作。毕竟这是一个不变的价值。

DECLARE @pay_date datetime 
SET @pay_date = (SELECT TOP 1 dbo.Docs.Pay_Date 
        FROM dbo.Docs 
        WHERE dbo.Docs.P_ID = P.P_ID 
        AND dbo.Docs.Cost_Name = 0x0000000000000008 
        AND dbo.Docs.Pay_Date >= @fromDate 
        ORDER BY dbo.Docs.Pay_Date) 

然后在查询

AND D.Pay_Date >= @pay_date 
+0

感谢您的回答,但是(抱歉,如果这听起来很愚蠢)如果我声明了一个变量并如上使用它,我将使用pay_date大于@pay_date的所有记录。我需要做的是为每个文档选择pay_date。我将编辑我的帖子,以显示我想完成什么样的逻辑:) – Misiu 2012-02-28 10:04:28