如何交换元组中的元素？

Question

我有一个非常具体的问题，我需要知道如何交换列表或元组中的元素。 我有一个名为板状的列表，我知道需要交换的元素。我如何交换它们？在具有二维数组的Java中，我可以轻松地执行标准交换技术，但在这里它表示元组分配是不可能的。

这里是我的代码：

board_state = [(0, 1, 2), (3, 4, 5), (6, 7, 8)] 

new = [1, 1] # [row, column] The '4' element here needs to be swapped with original 
original = [2, 1] # [row, column] The '7' element here needs to be swapped with new 

的结果应该是：

board_state = [(0, 1, 2), (3, 7, 5), (6, 4, 8)] 

我怎么换？

Answer 1

Tuples, like strings, are immutable: it is not possible to assign to the individual items of a tuple。

Lists是可变的，所以将您board_state到list的list S：

>>> board_state = [[0, 1, 2], [3, 4, 5], [6, 7, 8]] 

然后使用swapping two elements in a list标准Python成语：

>>> board_state[1][1], board_state[2][1] = board_state[2][1], board_state[1][1] 
>>> board_state 
[[0, 1, 2], [3, 7, 5], [6, 4, 8]]