2017-08-10 649 views
1

我有串在PHPPHP - 正则表达式,替换逗号分隔符,以分号

$str = '1,"4052","B00K6ED81S",,"Bottle, white - 6,5 l, WENKO","Good design!","Bottle, white 6,5 l, WENKO",,,"item","23",23,"23",23,31.22,31.22,,1,,,,0,8,"4",,0,,0,0,,0,,0,0,, 

有逗号分隔符。某处是空的字段,某处带有引号的字段(作为产品名称)。问题在于将分隔符替换为分号,但不要在产品名称中使用逗号。我需要这样的:

$str_replace = '1;"4052";"B00K6ED81S";;"Bottle, white - 6,5 l, WENKO";"Good design!";"Bottle, white 6,5 l, WENKO";;;"item";"23";23;"23";23;31.22;31.22;;1;;;;0;8;"4";;0;;0;0;;0;;0;0;;'; 

我试过这段代码:

$str = '1,"4052","B00K6ED81S",,"Bottle, white - 6,5 l, WENKO","Good design!","Bottle, white 6,5 l, WENKO",,,"item","23",23,"23",23,31.22,31.22,,1,,,,0,8,"4",,0,,0,0,,0,,0,0,,'; 

$str = preg_replace('/,,/', ',~~~,', $str); 
$str = preg_replace('/,,/', ',~~~,', $str); 

$pattern = '/(?<=\d),|(?<="),|~~~,/'; 
$str = preg_replace($pattern, ';', $str); 

结果:

1;"4052";"B00K6ED81S";;"Bottle, white - 6;5 l, WENKO";"Good design!";"Bottle, white 6;5 l, WENKO";;;"item";"23";23;"23";23;31.22;31.22;;1;;;;0;8;"4";;0;;0;0;;0;;0;0;; 

在产品的名称逗号替换以分号太:

"Bottle, white - 6;5 l, WENKO" 

如何我可以更正$ pattern来获得结果I需要什么?谢谢

+2

为什么不使用[str_getcsv()](http://php.net/manual/en/function.str-getcsv.php)将字符串解析为数组而不是试图“修复”它与正则表达式? –

+0

我不知道这个功能,谢谢! –

回答

1

我只是想尝试做一个代码,可以做到这一点老式的方式。
它发现“,并根据它是否是他们之间或他们的外面或不替换。

$str = '1,"4052","B00K6ED81S",,"Bottle, white - 6,5 l, WENKO","Good design!","Bottle, white 6,5 l, WENKO",,,"item","23",23,"23",23,31.22,31.22,,1,,,,0,8,"4",,0,,0,0,,0,,0,0,0'; 

$pos=1; // set $pos to make sure while loop does not end directly. 
$newstr = ""; 
$prevPos = 0; 
if($str[0]=='"') $str = " " .$str; // add space if the first char is a " 
$skip = false; // flag to know if replace should be done or not 

while($pos != false){ 
    $pos = strpos($str, '"', $prevPos); // find " in string after prevPos 
    $part = substr($str, $prevPos, $pos+1-$prevPos); // substring the part (first time it runs it will be '1,"' then '4052"') 
    if($skip){ // if it's between two " (a string) skip the replace 
     //echo "skip " . $part . "\n"; 
     $skip =!$skip; // change the flag 
     $newstr .= $part; 
    }else{ // if it's not in a string do the replace on the $part 
     //echo "!skip " . $part . "\n"; 
     $newstr .= str_replace(",", ";", $part);  
     $skip =!$skip; // change the flag. 
    } 
    $prevPos = $pos+1; // set new $prevPos 
} 

// if the loop ends and there is no more " in the string we need to replace , to ; on the rest of the string. 
// we know the loop ended at strlen($newstr), so that is the $part. 
if($pos<strlen($str)) $newstr .= str_replace(",", ";", substr($str, strlen($newstr))); 
echo $str . "\n"; 
echo $newstr; 

https://3v4l.org/CnSh8
它实际上执行得非常好。比我预期beeing一环,所有中频的和字符串操作

编辑;注意到,它并没有工作,如果第一项是一个字符串我添加一个空格只是为了确保该标志成为以正确的顺序
这可以很容易地进行修整。与trim()。
https://3v4l.org/hNLAF

+0

似乎有效!谢谢你的建议! –