FileInfo的功能PHP

Question

能有人给我如何使用fileinfo，更换的代码片段，如例如：

($_FILES["fileToUpload"]["type"] == "image/gif" 
|| $_FILES["fileToUpload"]["type"] == "image/jpeg" 
|| $_FILES["fileToUpload"]["type"] == "image/png") 

Answer 1

使用此：

$finfo = new finfo(); 
$fileinfo = $finfo->file($file, FILEINFO_MIME); 

$的FileInfo应该包含正确的MIME类型，您可以在类似的代码片段中使用，或者在switch语句中使用：

switch($fileinfo) { 
    case "image/gif": 
    case "image/jpeg": 
    case "image/png": 
     // Code 
     break; 
} 

Answer 2

$objInfo = new finfo(FILEINFO_MIME); 
list($strImageType, $strCharset) = $objInfo->file($_FILES['fileToUpload']['tmp_name']); 
//then use the variable $strImageType in your conditional 
if ($strImageType == "image/gif" || $strImageType == "image/jpeg" || $strImageType == "image/png") { 
//code 
}