我有一个shell脚本读取执行从Java,Shell脚本Shell脚本已经阅读操作
#!/bin/bash
echo "Type the year that you want to check (4 digits), followed by [ENTER]:"
read year
echo $year
我使用的Java API
ProcessBuilder pb = new ProcessBuilder("/bin/bash", "/junk/leaptest.sh");
final Process process = pb.start();
InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
while ((line = br.readLine()) != null) {
System.out.println(line);
}
System.out.println("Program terminated!");
在Java执行这个shell脚本的输入控制台我可以看到输出
类型要检查(4位)的年,然后按[ENTER]:
现在如何将值传递给我的脚本中的shell脚本实际的问题是如何在varialble“年”可以读
我已编辑的代码为每建议,但没有按” t工作在那里我们纠正它
ProcessBuilder pb = new ProcessBuilder("/bin/bash", "-c", "/junk/leaptest.sh");
final Process process = pb.start();
InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
/*
* OutputStream os = process.getOutputStream(); PrintWriter pw = new
* PrintWriter(os);
*/
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(process.getOutputStream()));
while ((line = br.readLine()) != null) {
System.out.println(line);
// pw.println("8999");
bw.write("2012");
}
System.out.println("Program terminated!");
感谢Alexr解析输出意味着什么?如何获得此 – anish