XML - 针对节点属性，推入Flash AS3阵列

Question

我试图将每个“问题”标签中的“txt”属性的内容推入AS3 Flash中名为“questions”的数组中。这是我的xml文件的摘录。

<question id='Q1' uId='99036' no_ans='2' txt='In a flat structure employees are not expected to provide their bosses with their opinions.' feedback='' type='MC' passingWeight='1' url='media/'> 
    <answer id='Q1A1' uId='311288' txt='True' weight='0'/> 
    <answer id='Q1A2' uId='311289' txt='False' weight='1'/> 
</question> 
<question id='Q2' uId='99037' no_ans='2' txt='In a hierarchy, information typically flows downward.' feedback='' type='MC' passingWeight='1' url='media/'> 
    <answer id='Q2A1' uId='311290' txt='True' weight='1'/> 
    <answer id='Q2A2' uId='311291' txt='False' weight='0'/> 
</question> 
<question id='Q3' uId='99038' no_ans='2' txt='Someone who keeps many projects going at one time is an example of someone who is flexible-time oriented.' feedback='' type='MC' passingWeight='1' url='media/'> 
    <answer id='Q3A1' uId='311292' txt='True' weight='1'/> 
    <answer id='Q3A2' uId='311293' txt='False' weight='0'/> 
</question> 

这是我在一个循环的尝试：

// get number of questions 
    trace(myXML.question.length()); 
    numberOfQuestions = myXML.question.length(); 

    //loop and push questions into questions array at top 
    for (var i:int = 0; i < numberOfQuestions; i++) { 
     trace("Hello."); 
     questions.push(myXML.question.@txt); 
     trace(questions); 
    } 

这只是推的问题，所有9日一旦进入阵列的每个位置。我想每个阵列位置1个问题。我不确定如何在问题标记中使用id属性来区分每个问题。

编辑：我尝试这样做，我可以从的processXML函数中（2）访问使用getQuestionAt问题文本，但不应超出它。

var myXML:XML; 
var myLoader:URLLoader = new URLLoader(); 
myLoader.load(new URLRequest("html/VUBZ7318CROSSCULTUREQUIZ/manifest.xml")); 
myLoader.addEventListener(Event.COMPLETE, processXML); 
function processXML(e:Event):void { 
    myXML = new XML(e.target.data); 

    //trace(myXML.question) 

    // get number of questions 
    trace(myXML.question.length()); 
    numberOfQuestions = myXML.question.length(); 

    //Question list 
    var questions:Object = {}; 
    //Extracting question from xml 
    for each (var item:XML in myXML.question) { 
     questions[item. @ id] = item. @ txt; 
    } 
    //Some method for fetching question from question list 
    function getQuestionAt(index:Number):String { 
     if (questions["Q" + index] == undefined) { 
      throw new Error("Wrong index for question!!!"); 
     } 
     return questions["Q"+index]; 
    } 

    //Getting question from list 
    trace("Here is question No 2:\t" + getQuestionAt(2)); 


} 

Answer 1

创建只有一个帧的新层，并且只要您的总帧数（例如6个长），就创建该帧的长度。然后把这个代码放在那个框架中。

//Question list 
var questions:Object; 
//Some method for fetching question from question list 
function getQuestionAt(index:Number):String{ 
    if(questions["Q"+index] == undefined){ 
     throw new Error("Wrong index for question!!!"); 
    } 
    return questions["Q"+index]; 
}  

然后，每当你想提问添加这些行到您的processXML功能

function processXML():*{ 
//.....Your 'myXML' is here.... 
questions = {}; 
//Extracting question from xml 
for each(var item:XML in myXML.question){ 
    questions[item.@id] = item.@txt; 
} 
} 

呼叫getQuestionAt。您可以在任何框架中调用该功能，因为它在所有框架上都是“可见的”。

Answer 2

您的XML设置只是一个错误。在AS3中，你需要一个根节点。根节点不可访问，它只是一种包装。在你的情况下，问题是你的根节点不可访问，这将使这些属性无法访问。所以把你的XML包装。我可能是错误的无法访问根节点属性，但我对你的XML是正确的。而添加包装只是使得更容易。

<questions> 
    <question id='Q1' uId='99036' no_ans='2' txt='In a flat structure employees are not expected to provide their bosses with their opinions.' feedback='' type='MC' passingWeight='1' url='media/'> 
     <answer id='Q1A1' uId='311288' txt='True' weight='0'/> 
     <answer id='Q1A2' uId='311289' txt='False' weight='1'/> 
    </question> 
    <question id='Q2' uId='99037' no_ans='2' txt='In a hierarchy, information typically flows downward.' feedback='' type='MC' passingWeight='1' url='media/'> 
     <answer id='Q2A1' uId='311290' txt='True' weight='1'/> 
     <answer id='Q2A2' uId='311291' txt='False' weight='0'/> 
    </question> 
    <question id='Q3' uId='99038' no_ans='2' txt='Someone who keeps many projects going at one time is an example of someone who is flexible-time oriented.' feedback='' type='MC' passingWeight='1' url='media/'> 
     <answer id='Q3A1' uId='311292' txt='True' weight='1'/> 
     <answer id='Q3A2' uId='311293' txt='False' weight='0'/> 
    </question> 
</questions> 

然后像这样获取属性。

var questions:XMLList = new XMLList(e.target.data.question) 
for each (var question:XML in questions){ 
    trace(question.@txt) 
} 

Answer 3

你有什么不是XML，而是一个XMLList，它是完全可以接受的。

你不需要循环。你可以像这样得到另一个XMLList。 XMLList就像一个XML数组，但在这种情况下，您将不会有完全形成的节点，而只是所有属性的内容。

它会是这样的：

var questionTxt:XMLList = yourQuestions.@txt;//yourQuestions contains your originalXMLList as shown above 

现在，您可以访问每一个文本元素为：

var stem:String = String(questionTxt[0]); 

如果由于某种原因，你绝对必须有一个数组，您可以这样做：

var questions:Array = new Array(); 
for (var i:int = 0; i< questionTxt.length(); i++) { 
    questions[i] = questionTxt[i]; 
} 

但是，它看起来像很多o因为你可以简单地使用XMLList，就像通过e4x访问它一样。你的全部目标是什么？

我只是看着你的问题多一点细心，你真正需要做的是这样的：

protected var questions:XMLList; 
public function processXML(e:Event):void { 
      myXML = XML(e.target.data); 
      questions = myXML.question; 

      // get number of questions 
      trace(myXML.question.length()); 
} 

public function getQuestionAt(index:Number):String { 
      if (questions[index] == undefined) { 
       throw new Error("Wrong index for question!!!"); 
      } 
      return questions[index].attribute('txt'); 
}  

public function get numberOfQuestions():int { 
    return myXML.question.length(); 
}