-1
为什么最好的做法是在这样的代码块中清空输入缓冲区中的“垃圾”?如果我没有,会发生什么?Java输入缓冲区垃圾
try{
age = scanner.nextInt();
// If the exception is thrown, the following line will be skipped over.
// The flow of execution goes directly to the catch statement (Hence, Exception is caught)
finish = true;
} catch(InputMismatchException e) {
System.out.println("Invalid input. age must be a number.");
// The following line empties the "garbage" left in the input buffer
scanner.next();
}