下面是一个可能有用的片段。我真的质疑你是否使用最好的方法,所以我做了一些假设(也许你只是没有给出足够的细节)。
我将xml解析为XmlDocument
以在代码中使用它。相关标签(“LinkedFile”)被拉出。每个标签被解析为Uri
。如果失败了,它就会失效并且再次尝试解析。最后将是包含正确解析的url的字符串列表。如果你真的需要,你可以在这个集合上使用你的正则表达式。
// this is for the interactive console
#r "System.Xml.Linq"
using System.Xml;
using System.Xml.Linq;
// sample data, as provided in the post.
string rawXml = "<SupportingDocs><LinkedFile>http://llcorp/ll/lljomet.dll/open/864606</LinkedFile><LinkedFile>http://llcorp/ll/lljomet.dll/open/1860632</LinkedFile><LinkedFile>%20http%3A%2F%2Fllenglish%2Fll%2Fll.exe%2Fopen%2F927515</LinkedFile><LinkedFile>%20http%3A%2F%2Fllenglish%2Fll%2Fll.exe%2Fopen%2F973783</LinkedFile></SupportingDocs>";
var xdoc = new XmlDocument();
xdoc.LoadXml(rawXml)
// will store urls that parse correctly
var foundUrls = new List<String>();
// temp object used to parse urls
Uri uriResult;
foreach (XmlElement node in xdoc.GetElementsByTagName("LinkedFile"))
{
var text = node.InnerText;
// first parse attempt
var result = Uri.TryCreate(text, UriKind.Absolute, out uriResult);
// any valid Uri will parse here, so limit to http and https protocols
// see https://stackoverflow.com/a/7581824/1462295
if (result && (uriResult.Scheme == Uri.UriSchemeHttp || uriResult.Scheme == Uri.UriSchemeHttps))
{
foundUrls.Add(uriResult.ToString());
}
else
{
// The above didn't parse, so check if this is an encoded string.
// There might be leading/trailing whitespace, so fix that too
result = Uri.TryCreate(Uri.UnescapeDataString(text).Trim(), UriKind.Absolute, out uriResult);
// see comments above
if (result && (uriResult.Scheme == Uri.UriSchemeHttp || uriResult.Scheme == Uri.UriSchemeHttps))
{
foundUrls.Add(uriResult.ToString());
}
}
}
// interactive output:
> foundUrls
List<string>(4) { "http://llcorp/ll/lljomet.dll/open/864606", "http://llcorp/ll/lljomet.dll/open/1860632", "http://llenglish/ll/ll.exe/open/927515", "http://llenglish/ll/ll.exe/open/973783" }
您在https后匹配两个斜线。那些出现在前两个,但不是第二个。可能还有其他问题,但这是我看到的第一个问题。 – BurnsBA