这不是没有工作,但只是我很困惑如何做到这一点,我想根据用户的偏好,从早先选择我的数据库中取值。 这些步骤将采取我的过程:用于HTML的PHP POST选择使用另一个POST
- 用户将图像中选择(将添加HTML的图像,然后将掀起它在另一选择)
- 将持续到达到最后阶段
- 最后阶段将有3个选择(下拉菜单),其中2将根据什么用户的选(如国家,州DD)
我的PHP改变内容:
else if ($_POST["data_key"]=="last")
{
$final_arr;
$fetcher_theme = $_POST["themeid"];
$fetcher_category= $_POST["themecategory"];
$fetcher_product= $_POST["themeproduct"];
$fetcher_cover = $_POST["ctitle"];
$myquery="SELECT DISTINCT Layout.* FROM Layout,Products,Occasion, Cover, Theme
WHERE Layout.product=$fetcher_product
AND Layout.occasion=$fetcher_category
AND Layout.theme=$fetcher_theme
AND Layout.cover=$fetcher_cover;";
$results=$DB->fetchAll($myquery);
foreach ($results as $row) {
$row["current"]="size";
unset($row["pixfizzId"]);
$final_arr[]=$row;
}
echo json_encode($final_arr);
}
else if ($_POST["data_key"]=="size")
{
$final_arr;
$fetcher = $_POST["selected_id"];
$fetcher_theme = $_POST["themeid"];
$fetcher_category= $_POST["themecategory"];
$fetcher_product= $_POST["themeproduct"];
$fetcher_cover = $_POST["ctitle"];
$fetcher_size = $_POST["stitle"];
$myquery="SELECT DISTINCT Size.stitle FROM Layout,Products,Occasion, Size, Theme
WHERE Layout.product=$fetcher_product
AND Layout.occasion=$fetcher_category
AND Layout.theme=$fetcher_theme
AND Layout.size=$fetcher_size
AND Layout.size=Size.id";
$results=$DB->fetchAll($myquery);
foreach ($results as $row) {
$row["current"]="finishing";
unset($row["pixfizzId"]);
$final_arr[]=$row;
}
echo json_encode($final_arr);
}
else if ($_POST["data_key"]=="finishing")
{
$final_arr;
$fetcher = $_POST["selected_id"];
$fetcher_theme = $_POST["themeid"];
$fetcher_category= $_POST["themecategory"];
$fetcher_product= $_POST["themeproduct"];
$fetcher_cover = $_POST["ctitle"];
$fetcher_size = $_POST["stitle"];
$fetcher_finishing = $_POST["ftitle"];
$myquery="SELECT DISTINCT Finishing.ftitle FROM Layout,Products,Occasion, Size, Cover, finishing, Theme
WHERE Layout.product=$fetcher_product
AND Layout.occasion=$fetcher_category
AND Layout.theme=$fetcher_theme
AND Layout.size=$fetcher_size
AND Layout.cover=$fetcher_cover
AND Layout.finishing=$fetcher_finishing";
$results=$DB->fetchAll($myquery);
foreach ($results as $row) {
$row["current"]="finishing";
unset($row["pixfizzId"]);
$final_arr[]=$row;
}
echo json_encode($final_arr);
}}
我的引擎JS(什么我给你):
myItem.setId(jsonData[i].id);
myItem.setImg(jsonData[i].image);
myItem.setTitle(jsonData[i].title);
我的JS选择(打印HTML):
myString +="<a>Sizes: </a><br><select id='sizesSelect' style=' width:200px'></select><br><br>";
myString +="<a>Cover: </a><br><select id='coverSelect' style=' width:200px'><br></select><br><br>";
myString +="<a>Finishing: </a><br><select id='finishingSelect' style=' width:200px'></select><br><br><br>";
追加到在JS选择:
myString +="<script>$('#sizesSelect').append('<option val="+i+">"+this.getSize()+"</option>')</script>";
现在我需要知道如何再次发布到我的PHP服务器以获取其他选择的值(请参阅img)。
选择尺寸 - >更新封面 - >选择封面 - >更新精加工 - >选择整理
'$更改为MyQuery =“SELECT DISTINCT布局* FROM布局,产品展示,场合,封面,主题 WHERE Layout.product = $ fetcher_product 和Layout.occasion = $ fetcher_category 和Layout.theme = $ fetcher_theme。 AND Layout.cover = $ fetcher_cover;“;'这是一个字符串... – user5173426
考虑移动到http://codereview.stackexchange.com/ –
我知道如何输入我的查询,我需要POST如何完成。 –