除匹配值外，我如何匹配所有内容？

Question

我有this regex：

/(\[.*?\])/g 

现在我想改变这种状况正则表达式匹配除电流匹配一切。我怎样才能做到这一点？

例如：

当前正则表达式：

here is some text [anything123][/21something] and here is too [sometext][/afewtext] and here 

//     ^^^^^^^^^^^^^^^^^^^^^^^^^^^     ^^^^^^^^^^^^^^^^^^^^^ 

我想这一点：

here is some text [anything123][/21something] and here is too [sometext][/afewtext] and here 
// ^^^^^^^^^^^^^^^^^^       ^^^^^^^^^^^^^^^^^      ^^^^^^^^^ 

Answer 1

比赛里面有什么或捕获只是表面现象^{the trick}

\[.*?\]|([^[]+) 

See demo at regex101

演示：

var str = 'here is some text [anything123][/21something] and here is too [sometext][/afewtext] and here'; 
 

 
var regex = /\[.*?\]|([^[]+)/g; 
 
var res = ''; 
 

 
// Do this until there is a match 
 
while(m = regex.exec(str)) { 
 
    // If first captured group present 
 
    if(m[1]) { 
 
     // Append match to the result string 
 
     res += m[1]; 
 
    } 
 
} 
 

 
console.log(res); 
 
document.body.innerHTML = res; // For DEMO purpose only