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我已经搜索了很长时间,但没有找到任何有关如何执行此操作的好资源。 api需要一个窗体参数“user_id”(现在发送它的urlpath不是表单参数)和其他“文件”的视频文件。请使用URLSession Task或iOS的任何库提供一些代码示例。Swift3视频文件上传以及一个表单参数(可以从表单跳过并作为url路径发送)

试过Alamofire:

Alamofire.upload(multipartFormData: { (multipartFormData) in 
     multipartFormData.append(self.fileurl, withName: "file") 
    }, to:"http://www.www.www/upload/8590", 
     headers: ["Authorization": "Bearer \(SharedPreferences.preferences.getKeyValue(key: Constants.AUTH_TOKEN_key))"]) 
    { (result) in 
     switch result { 
     case .success(let upload, _ , _): 

      upload.uploadProgress(closure: { (progress) in 

       print("uploding>>>>>>") 
      }) 

      upload.responseJSON { response in 
       print(response) 
       print("done") 

      } 

     case .failure(let encodingError): 
      print("failed") 
      print(encodingError) 

     } 

这从服务器说使用UTF-8编码它不能读头的第一个字节抛出500。

message = "An Error OccuredInvalid header string: 'utf8' codec can't decode byte 0x9b in position 1: invalid start byte"; 
result = "Traceback (most recent call last):\n File \"/var/www/wb_ios/wb_app/views.py\", line 94, in post\n user_auth = jwt_decode_handler(auth).get('sub')\n File \"/usr/local/lib/python2.7/dist-packages/rest_framework_jwt/utils.py\", line 104, in jwt_decode_handler\n unverified_payload = jwt.decode(token, None, False)\n File \"/usr/local/lib/python2.7/dist-packages/jwt/api_jwt.py\", line 70, in decode\n payload, signing_input, header, signature = self._load(jwt)\n File \"/usr/local/lib/python2.7/dist-packages/jwt/api_jws.py\", line 177, in _load\n raise DecodeError('Invalid header string: %s' % e)\nDecodeError: Invalid header string: 'utf8' codec can't decode byte 0x9b in position 1: invalid start byte\n"; 
status = 500; 

}

另外,我可以使用邮递员成功地发送视频。使用图像中显示的表单数据字段。 body Headers

终于我也试过:

let url = NSURL(string: "http://www.www.www/upload/8590") 
    let request = NSMutableURLRequest(url: url! as URL) 
    let boundary = "------------------------your_boundary" 

    request.httpMethod = "POST" 
    request.setValue("ios", forHTTPHeaderField: "client") 
    request.setValue(Constants.AUTH_KEY, forHTTPHeaderField: Constants.AUTH_KEY_key) 
    request.setValue("Bearer " + SharedPreferences.preferences.getKeyValue(key: Constants.AUTH_TOKEN_key)!, forHTTPHeaderField: Constants.AUTH_AUTHORIZATION_key) 
    request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type") 
    var movieData: NSData? 
    do { 
     movieData = try NSData(contentsOfFile: fileurl.path, options: NSData.ReadingOptions.alwaysMapped) 
     print(movieData) 
    } catch _ { 
     movieData = nil 
     return 
    } 

    let body = NSMutableData() 

    // change file name whatever you want 
    let filename = "upload.mov" 
    let mimetype = "video/mov" 

    body.append("--\(boundary)\r\n".data(using: String.Encoding.utf8)!) 
    body.append("Content-Disposition:form-data; name=\"file\"; filename=\"\(filename)\"\r\n".data(using: String.Encoding.utf8)!) 
    body.append("Content-Type: \(mimetype)\r\n\r\n".data(using: String.Encoding.utf8)!) 
    body.append(movieData! as Data) 
    request.httpBody = body as Data 

    let session = URLSession.shared 
    let task = session.dataTask(with: request as URLRequest) { 
     (data, response, error) in 

     guard let _:NSData = data as! NSData, let _:URLResponse = response, error == nil else { 
      print("error") 
      return 
     } 

     let dataString = NSString(data: data!, encoding: String.Encoding.utf8.rawValue) 
     print(dataString) 
    } 

    task.resume() 

这也引发错误是这样的:

{"status":500,"message":"An Error Occuredu'file'","result":"Traceback (most recent call last):\n File \"/var/www/wb_ios/wb_app/views.py\", line 104, in post\n file_obj = request.data['file']\n File \"/usr/local/lib/python2.7/dist-packages/django/utils/datastructures.py\", line 85, in __getitem__\n raise MultiValueDictKeyError(repr(key))\nMultiValueDictKeyError: \"u'file'\"\n"}) 
+0

在第二次考试ple(URLSession)服务器不希望表单数据中的文件名,但我认为我没有任何区别。 如果无法正确上传表单,服务器无法正确读取字典。 –

回答

0

Swift3.0

Alamofire.upload(multipartFormData: { MultipartFormData in 
      for (key, value) in parameter { 
       MultipartFormData.append((value as AnyObject).data(using: String.Encoding.utf8.rawValue)!, withName: key) 
      } 

// here you can upload only mp4 video 
       multipartFormData.append(self.fileurl!, withName: "file", fileName: "video.mp4", mimeType: "video/mp4") 
// here you can upload any type of video    
       multipartFormData.append((self.fileurl.data(using: String.Encoding.utf8, allowLossyConversion: false))!, withName: "File") 

      print(MultipartFormData) 
     },to:"http://www.www.www/upload/8590",headers: ["Authorization": "Bearer \(SharedPreferences.preferences.getKeyValue(key: Constants.AUTH_TOKEN_key))"] 
      ) 
     { (result) in 

      switch result { 
      case .success(let upload, _, _): 
       upload.uploadProgress(closure: { (progress) in 
        print("Upload Progress: \(progress.fractionCompleted)") 
       }) 
       upload.responseJSON { response in 
        print(response.result.value ?? String()) 
        print(response.data ?? NSData()) 
        // send to completion block 
        completion(response.data as AnyObject? ?? NSData()) 
       } 

      case .failure(let encodingError): 
       print(encodingError) 
       errorOccured(encodingError as NSError?) 

      } 
     } 
+0

in line multipartFormData.append((“VIDEO”.data(using:String.Encoding.utf8,allowLossyConversion:false))!, withName:“Type”) 什么是“VIDEO”? –

+0

加入你的视频网址,你只需要使用这个 multipartFormData.append(self.fileurl!,withName:“file”,fileName:“video.mp4”,mimeType:“video/mp4”)并注释该行.Please让我知道它是否有效。 –

+0

一旦我为ipad构建应用程序,我厌倦了构建失败。没想到iOS比android更麻烦。将尽快发布结果。 –

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