试图让非对象的属性笨3

Question

谁能给我解决了这个问题上的笨3

布局

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型号

function detailpPost($slug) 
{ 
    $this->db->where('url_post',$slug); 
    return $this->db->get('posting', array('url_post' => $slug))->row(); 

} 

为MyModel

public function getCategoryPost(){ 
    $query="SELECT * FROM kategori"; 
    $q=$this->db->query($query); 
    $data=array(); 
    if($q->num_rows() > 0){ 
     foreach ($q->result_array() as $row){ 
      $data[$row['id_kategori']] = $row['nama_kategori']; 
     } 
     return $data; 
    } 
} 

Answer 1

替换线19与下面的代码

$nama_kategori = $kategori[$row['id_kategoripost']];