Oracle每日统计/一年以上的平均值

Question

我在特定的时间段内拉取两条信息，但我想获取一个标记的日平均值和另一个标记的每日计数。我不确定如何在特定的时间段内进行日常平均，任何人都可以提供一些建议？下面是我如何处理这个问题的第一个想法，但改变每一个日期都会很烦人。任何帮助表示赞赏感谢

SELECT COUNT(distinct chargeno), to_char(chargetime, 'mmddyyyy') AS chargeend 
FROM batch_index WHERE plant=1 AND chargetime>to_date('2012-06-18:00:00:00','yyyy-mm-dd:hh24:mi:ss') 
AND chargetime<to_date('2012-07-19:00:00:00','yyyy-mm-dd:hh24:mi:ss') 
group by chargetime; 

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The working version of the daily sum 
SELECT to_char(bi.chargetime, 'mmddyyyy') as chargtime, SUM(cv.val)*0.0005 
FROM Charge_Value cv, batch_index bi WHERE cv.ValueID =97 
AND bi.chargetime<=to_date('2012-07-19','yyyy-mm-dd') 
AND bi.chargeno = cv.chargeno AND bi.typ=1 
group by to_char(bi.chargetime, 'mmddyyyy') 

Answer 1

好像在想的组更改为当天的第一个 - 不是时候......（加上我不认为你需要指定所有那些0的几秒钟..）

SELECT COUNT(distinct chargeno), to_char(chargetime, 'mmddyyyy') AS chargeend 
FROM batch_index WHERE plant=1 AND chargetime>to_date('2012-06-18','yyyy-mm-dd') 
AND chargetime<to_date('2012-07-19','yyyy-mm-dd') 
group by to_char(chargetime, 'mmddyyyy') ; 

Answer 2

不是100％我下面你的问题，但如果你只想做集合体（总和，平均），然后做到这一点。我在汇总扔以防万一这就是你要找的

with fakeData as(
    select trunc(level *.66667) nr 
     , trunc(2*level * .33478) lvl --these truncs just make the doubles ints 
     ,trunc(sysdate+trunc(level*.263784123)) dte --note the trunc, this gets rid of the to_char to drop the time 
    from dual 
connect by level < 600 
) --the cte is just to create fake data 
--below is just some aggregates that may help you 
select sum(nr) daily_sum_of_nr 
    , avg(nr) daily_avg_of_nr 
    , count(distinct lvl) distinct_lvls_per_day 
    , count(lvl) count_of_nonNull_lvls_per_day 
    , dte days 
    from fakeData 
group by rollup(dte) 

--IF您想查询提供一个总的范围内，你可以使用汇总（http://psoug.org/reference/rollup.html）