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我已经能够实现自动完成,只是我想要做的就是使用php的json_encode函数。如何编码jQuery的输入到jquery ui自动完成?
这里是我当前的代码:
<?php
$host = "localhost";
$user = "root";
$password = "";
$db = "isproj2";
// open connection
$connection = mysql_connect($host, $user, $password) or die ("Unable to connect!");
// select database
mysql_select_db($db) or die ("Unable to select database!");
$text = mysql_real_escape_string($_GET['term']);
$query = "Select SupplierName, SupplierID from tbl_supplier where SupplierName LIKE '%$text%'";
$result = mysql_query($query);
$json = '[';
$first = true;
while($row = mysql_fetch_array($result))
{
if (!$first) { $json .= ','; } else { $first = false; }
$json .= '{"label":"'.$row['SupplierName'].'","value":"'.$row['SupplierID'].'" }';
}
$json .= ']';
echo $json;
?>
先生/女士你的答案会是很大的帮助。谢谢++
JSON无效。您没有在每行的末尾附加逗号(不要放在最后一行)。 – Flukey 2012-04-08 10:46:21