我面临着YoutubePlayer一个问题,我把它放在这样一个片段中:Android和YoutubePlayer:错误创建YouTubePlayerView
public class VideoFragment extends YouTubePlayerSupportFragment {
public VideoFragment() { }
public static Fragment newInstance(String url) {
VideoFragment f = new VideoFragment();
Bundle b = new Bundle();
b.putString("url", url);
f.setArguments(b);
f.init(Constants.YOUTUBE_DEV_KEY);
return f;
}
private void init(String api) {
initialize(api, new YouTubePlayer.OnInitializedListener() {
@Override
public void onInitializationFailure(YouTubePlayer.Provider arg0, YouTubeInitializationResult arg1) { }
@Override
public void onInitializationSuccess(YouTubePlayer.Provider provider, YouTubePlayer player, boolean wasRestored) {
if (!wasRestored) {
player.cueVideo(getArguments().getString("url"));
}
}
});
}
我这样称呼它从我的其他片段:
Fragment f = VideoFragment.newInstance(User.getVideoId());
getFragmentManager().beginTransaction().replace(R.id.fragment_container, f).commit();
不过,我不断收到此错误:
YouTubeAndroidPlayerAPI:错误创建YouTubePlayerView com.google.android.youtube.player.internal.w $ a:由 引发的异常在 com.google.android.youtube.api.jar.client.RemoteEmbeddedPlayer com.google.android.youtube中调用构造函数引发的异常。 player.internal.wa(来源不明) 在com.google.android.youtube.player.internal.wa(来源不明) 在com.google.android.youtube.player.internal.wa(来源不明) 在COM .google.android.youtube.player.internal.ac.a(Unknown Source) at com.google.android.youtube.player.YouTubePlayerView.a(Unknown Source) at com.google.android.youtu be.player.YouTubePlayerView $ 1.a(未知 来源) at com.google.android.youtube.player.internal.rg(未知来源) at com.google.android.youtube.player.internal.r $ ca(未知来源) at com.google.android.youtube.player.internal.r $ ba(Unknown Source) at com.google.android.youtube.player.internal.r $ a.handleMessage(Unknown Source)。 ...
尝试导入程序兼容性23.0.1而不是最新版本的[本网站]说(http://www.mzan.com/article/33614190-youtubeplayersupportfragment-and-appcompatactivity-error.shtml)。 – noogui