我有一个AspxGridView,当我双击一行,它显示一个模式窗口。我想要做的是,将一列的值发送到ModalWindow中的AspxLabel。但我无法做到这一点,在GridView我使用ClientSideEvents RowDblClick获取行值。下面是代码:AspxGridView与模式窗口,
GridView控件:
<dxwgv:ASPxGridView ID="gw_Parameters" runat="server"
CssFilePath="~/App_Themes/Aqua/{0}/styles.css" CssPostfix="Aqua"
AutoGenerateColumns="False" ClientInstanceName="grid"
OnCustomDataCallback="gw_Parameters_CustomDataCallback">
<ClientSideEvents RowDblClick="function(s, e) {
grid.GetValuesOnCustomCallback(e.visibleIndex, ShowModalWindow())
}" />
脚本:
function ShowModalWindow(val)
{
pcc_Question.Show();
lblCQuestionText.SetText(val);
}
和C#:
protected void gw_Parameters_CustomDataCallback(object sender, ASPxGridViewCustomDataCallbackEventArgs e)
{
int visibleIndex = Convert.ToInt32(e.Parameters);
string fieldName = string.Empty;
if (gw_Parameters.VisibleColumns[0] is GridViewCommandColumn)
fieldName = ((GridViewDataColumn)gw_Parameters.VisibleColumns[3]).FieldName;
else
fieldName = ((GridViewDataColumn)gw_Parameters.VisibleColumns[2]).FieldName;
e.Result = gw_Parameters.GetRowValues(visibleIndex, fieldName);
}
感谢您的帮助,
穆罕默德衬线Tozlu