我有这样需要的输出
[[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
所需的输出列表:
[{1:"one",2:"two"},{1:"one"},{3:"three",4:"four"},{3:"three"}]
有人能告诉我如何进行?
我有这样需要的输出
[[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
所需的输出列表:
[{1:"one",2:"two"},{1:"one"},{3:"three",4:"four"},{3:"three"}]
有人能告诉我如何进行?
迭代列表的列表以将其添加到另一个列表。
list_1 = [[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
list_2 = []
for list in list_1:
for dictionary in list:
list_2.append(dictionary)
print(list_2) # [{1: 'one', 2: 'two'}, {1: 'one'}, {3: 'three', 4: 'four'}, {3: 'three'}]
不!得到这个作为输出:
@ArohiGupta我的错误;我编辑了答案,再试一次。 –
任何想法如何从输出中删除“unicode”? –
你可以试试这个:
from itertools import chain
l = [[{1:"one",2:"two"},{1:"one"}],[{3:"three",4:"four"},{3:"three"}]]
new_l = list(chain(*l))
最终输出:
[{1: 'one', 2: 'two'}, {1: 'one'}, {3: 'three', 4: 'four'}, {3: 'three'}]
这就是所谓扁平化的列表。请参阅https://stackoverflow.com/questions/952914/making-a-flat-list-out-of-list-of-lists-in-python,https://stackoverflow.com/questions/406121/flattening-a -shallow一览中-蟒?noredirect = 1&LQ = 1。一个好的答案是'[子列表中项目的L子项列表]' – Stuart