2016-09-22 74 views
0

我想在使用'formtools'保存之前预览窗体。当我访问后它提供了以下错误: 请求方法:GET 请求URL:http://127.0.0.1:8000/post/TypeError at/post/render_to_response()得到了一个意外的关键字参数'context_instance'

Django Version: 1.10.1 
Python Version: 3.5.2 
Installed Applications: 
['django.contrib.admin', 
'django.contrib.auth', 
'django.contrib.contenttypes', 
'django.contrib.sessions', 
'django.contrib.messages', 
'django.contrib.staticfiles', 
'pagedown', 
'bootstrapform', 
'contact', 
'crispy_forms', 
'formtools', 
'member'] 
Installed Middleware: 
['django.middleware.security.SecurityMiddleware', 
'django.contrib.sessions.middleware.SessionMiddleware', 
'django.middleware.common.CommonMiddleware', 
'django.middleware.csrf.CsrfViewMiddleware', 
'django.contrib.auth.middleware.AuthenticationMiddleware', 
'django.contrib.messages.middleware.MessageMiddleware', 
'django.middleware.clickjacking.XFrameOptionsMiddleware'] 



Traceback: 

File "/home/ohid/test_venv/lib/python3.5/site-packages/django/core/handlers/exception.py" in inner 
    39.    response = get_response(request) 

File "/home/ohid/test_venv/lib/python3.5/site-packages/django/core/handlers/base.py" in _legacy_get_response 
    249.    response = self._get_response(request) 

File "/home/ohid/test_venv/lib/python3.5/site-packages/django/core/handlers/base.py" in _get_response 
    187.     response = self.process_exception_by_middleware(e, request) 

File "/home/ohid/test_venv/lib/python3.5/site-packages/django/core/handlers/base.py" in _get_response 
    185.     response = wrapped_callback(request, *callback_args, **callback_kwargs) 

File "/home/ohid/test_venv/lib/python3.5/site-packages/formtools/preview.py" in __call__ 
    34.   return method(request) 

File "/home/ohid/test_venv/lib/python3.5/site-packages/formtools/preview.py" in preview_get 
    58.    context_instance=RequestContext(request)) 

Exception Type: TypeError at /post/ 
Exception Value: render_to_response() got an unexpected keyword argument 'context_instance' 

这里是我的preview.py:

from formtools.preview import FormPreview 
from django.http import HttpResponseRedirect 
from .models import Person 

    class PersonFormPreview(FormPreview): 
     form_template = 'member/person_form.html' 
     preview_template = 'member/person_review.html' 
     model = Person 

     def done(self, request, cleaned_data): 
      self.form.save() 
      # Do something with the cleaned_data, then redirect 
      # to a "success" page. 
      return HttpResponseRedirect('/form/success') 

这里是我的网址:

from .preview import PersonFormPreview 
from .forms import MemberForm 
from django import forms 

url(r'^post/$', PersonFormPreview(MemberForm)), 

我该如何解决这个错误?

+1

您是否尝试将问题标题直接复制到Google? – Sayse

回答

1

我在LIB/python3.5 /站点包/ formtools/preview.py文件中的一些变化解决它。在这里,我首先更改render_to_response来渲染,然后从参数中移除context_instance = RequestContext(request)。假设post_post方法现在看起来像:

def post_post(self, request): 
     """ 
     Validates the POST data. If valid, calls done(). Else, redisplays form. 
     """ 
     form = self.form(request.POST, auto_id=self.get_auto_id()) 
     if form.is_valid(): 
      if not self._check_security_hash(
        request.POST.get(self.unused_name('hash'), ''), 
        request, form): 
       return self.failed_hash(request) # Security hash failed. 
      return self.done(request, form.cleaned_data) 
     else: 
      return render(request, self.form_template, 
       self.get_context(request, form)) 

希望这会帮助他人。

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