<?php
include "db.php";
$username=$_POST['username'];
$email=$_POST['email'];
$query="SELECT * FROM members where username = '".mysql_real_escape_string($username)."'";
$result=mysql_query($query)or die(mysql_error());
$user = mysql_fetch_assoc($result);
mysql_close();
?> <br /> <p></p>
Welcome back! Your details below: <br /><br />
<table border="1" cellspacing="2" cellpadding="5">
<tr>
<th>First Name</th>
<th>Last Name</th>
<th>User Name</th>
<th>Email</th>
<th>Age</th>
</tr>
<?php
$firstname= $user['firstname'];
$lastname= $user['lastname'];
$username= $user['username'];
$email= $user['email'];
$age= $user['age'];
?>
<tr>
<td><? echo $firstname ?></td>
<td><? echo $lastname ?></td>
<td><? echo $username ?></td>
<td><? echo $email ?></td>
<td><? echo $age ?></td>
</tr>
</table>
伙计们,我使用此代码来显示用户的详细信息,但它仍然不显示记录。显示用户的记录从数据库
这段代码有什么问题?嗯...没有错误,但它不起作用。
:'(
Mayumi,如果你找到了解决方案,从下面选择并回答,这很好。 – Codex73 2010-07-15 11:36:48