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我想为图库做导航按钮。当我点击下一个时,它传递一个参数来指示需要执行哪个动作,例如下一个。相反,我得到一个404错误。这里是代码的细节:Url.Action路由不正确
RouteConfig.cs:
public static void RegisterRoutes(RouteCollection routes)
{
routes.IgnoreRoute("{resource}.axd/{*pathInfo}");
routes.MapRoute(
name: "Default",
url: "{controller}/{action}/{actionType}",
defaults: new { controller = "Home", action = "Index", actionType = UrlParameter.Optional }
);
}
查看:
<div class="post-navi">
<a class="prev" href="@Url.Action("Portfolio", "Gallery", new { actionType = "Prev" })"><</a>
<a class="next" href="@Url.Action("Portfolio", "Gallery", new { actionType = "Next" })">></a>
<div class="clear"></div>
</div>
控制器:
public class GallaryController : Controller
{
//
// GET: /Gallary/Portfolio/actionType
public ActionResult Portfolio(string actionType)
{
List<Gallary> gallery = null;
if (actionType == "Prev")
{
gallery = Gallary.getPortfolioPrev();
}
else if (actionType == "Next")
{
gallery = Gallary.getPortfolioNext();
}
else
{
gallery = Gallary.getPortfolioGallery();
}
return View(gallery);
}
}
谢谢。我愚蠢的错误。 –
一切都很好...完全人为的错误:) –