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我已经部署在Tomcat的8 web应用程序这是我有问题的servlet:确定从HTTP响应头丢失
@WebServlet(name = "Start", urlPatterns = {"/start"})
public class StartServlet extends HttpServlet {
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String requestBodyStr = request.getReader().lines().collect(Collectors.joining(System.lineSeparator()));
StartRequest startRequest = JsonUtil.parseStartRequest(requestBodyStr);
if (startRequest == null) {
response.sendError(HttpServletResponse.SC_BAD_REQUEST);
return;
}
response.setStatus(HttpServletResponse.SC_OK);
String responseBody = getResponseBody();
try (PrintWriter out = response.getWriter()) {
out.print(responseBody);
}
}
}
如果我做出这个servlet的请求,则响应没有正常工作状态消息,它只是:
HTTP/1.1 200
如何给响应添加OK?
200是一个好的回应。你应该注意到返回代码值,而不是期望一些文本。但是,如果需要,则需要将其添加到响应流中。 – jr593
您无法更改标准响应代码 – sForSujit