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我想这个代码与Java转换成C＃（位于here）帮我处理代码转换为C＃
我有一些WinForm的经验，但不是很多与像素上一个winform应用程序的绘图。
我觉得相当有信心，我可以在大部分的子方法转换即时通讯如何我想提请indiviual像素在屏幕上
任何帮助或工具转换过的Java与C＃将只是不清楚大大apprehsated
// Buddhabrot
// j.tarbell January, 2004
// Albuquerque, New Mexico
// complexification.net
// based on code by Paul Bourke
// astronomy.swin.edu.au/~pbourke/
// Processing 0085 Beta syntax update
// j.tarbell April, 2005
int dim = 800; // screen dimensions (square window)
int bailout = 200; // number of iterations before bail
int plots = 10000; // number of plots to execute per frame (x30 = plots per second)
// 2D array to hold exposure values
int[] exposure = new int[dim*dim];
int maxexposure; // maximum exposure value
int time = 0;
int exposures = 0;
boolean drawing;
PFont metaBold;
// MAIN ----------------------------------------------------------------
void setup() {
// set up drawing area
size(800,800,P3D);
background(0);
// take it nice and easy
framerate(15);
// load typeface
metaBold = loadFont("Arial-48.vlw");
}
void draw() {
plotPlots();
time++;
if (time%30==0) {
// show progress every 2 seconds or so...
findMaxExposure();
renderBrot();
// show exposure value
fill(255);
noStroke();
textFont(metaBold, 14);
text("bailout: "+bailout+" exposures: "+exposures, 5, dim-6);
}
}
void plotPlots() {
float x, y;
// iterate through some plots
for (int n=0;n<plots;n++) {
// Choose a random point in same range
x = random(-2.0,1.0);
y = random(-1.5,1.5);
if (iterate(x,y,false)) {
iterate(x,y,true);
exposures++;
}
}
}
void renderBrot() {
// draw to screen
for (int i=0;i<dim;i++) {
for (int j=0;j<dim;j++) {
float ramp = exposure[i*dim+j]/(maxexposure/2.5);
// blow out ultra bright regions
if (ramp > 1) {
ramp = 1;
}
color c = color(int(ramp*255), int(ramp*255), int(ramp*255));
set(j,i,c);
}
}
}
// Iterate the Mandelbrot and return TRUE if the point exits
// Also handle the drawing of the exit points
boolean iterate(float x0, float y0, boolean drawIt) {
float x = 0;
float y = 0;
float xnew, ynew;
int ix,iy;
for (int i=0;i<bailout;i++) {
xnew = x * x - y * y + x0;
ynew = 2 * x * y + y0;
if (drawIt && (i > 3)) {
ix = int(dim * (xnew + 2.0)/3.0);
iy = int(dim * (ynew + 1.5)/3.0);
if (ix >= 0 && iy >= 0 && ix < dim && iy < dim) {
// rotate and expose point
exposure[ix*dim+iy]++;
}
}
if ((xnew*xnew + ynew*ynew) > 4) {
// escapes
return true;
}
x = xnew;
y = ynew;
}
// does not escape
return false;
}
void findMaxExposure() {
// assume no exposure
maxexposure=0;
// find the largest density value
for (int i=0;i<dim;i++) {
for (int j=0;j<dim;j++) {
maxexposure = max(maxexposure,exposure[i*dim+j]);
}
}
}
// Buddhabrot
// j.tarbell January, 2004
没有Java的 - 它的处理 – 2009-06-25 20:00:31
你能解释一些什么是缺少的（我不知道很多关于java） – Crash893 2009-06-25 20:49:15
处理是一种编译到JVM的不同语言 - 这不是Java。 Processing是用Java构建的，可以生成JVM字节码并调用Java，但是没有Java-> C＃转换器会知道如何处理它。 – 2009-06-25 20:57:22