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我想从我的S3存储桶与s3cmd路径样式URL访问对象。这对Java SDK来说没有问题。s3cmd节点名称,服务名称提供,或不知道
s3Client.setS3ClientOptions(S3ClientOptions.builder()
.setPathStyleAccess(true).build());
我想对s3cmd做同样的事情。我在s3conf文件进行设置:
host_base = s3.eu-central-1.amazonaws.com
host_bucket = s3.eu-central-1.amazonaws.com/%(bucket)s
这适用于桶上市:
$ s3cmd ls
2016-08-24 12:36 s3://test
当试图列出斗我得到以下错误的所有对象:
Traceback (most recent call last):
File "/usr/local/bin/s3cmd", line 2919, in <module>
rc = main()
File "/usr/local/bin/s3cmd", line 2841, in main
rc = cmd_func(args)
File "/usr/local/bin/s3cmd", line 120, in cmd_ls
subcmd_bucket_list(s3, uri)
File "/usr/local/bin/s3cmd", line 153, in subcmd_bucket_list
response = s3.bucket_list(bucket, prefix = prefix)
File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 297, in bucket_list
for dirs, objects in self.bucket_list_streaming(bucket, prefix, recursive, uri_params):
File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 324, in bucket_list_streaming
response = self.bucket_list_noparse(bucket, prefix, recursive, uri_params)
File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 343, in bucket_list_noparse
response = self.send_request(request)
File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 1081, in send_request
conn = ConnMan.get(self.get_hostname(resource['bucket']))
File "/usr/local/lib/python2.7/site-packages/S3/ConnMan.py", line 192, in get
conn.c.connect()
File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 836, in connect
self.timeout, self.source_address)
File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py", line 557, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
gaierror: [Errno 8] nodename nor servname provided, or not known