Oracle案例陈述

请考虑下面的这个表格并给出结果集。现在，只要满足其中一个条件，我如何才能获得一条记录。Oracle案例陈述

SQL> SELECT ename 
    2 ,  job 
    3 ,  CASE 
    4   WHEN sal < 1000 
    5   THEN 'Low paid' 
    6   WHEN sal BETWEEN 1001 AND 2000 
    7   THEN 'Reasonably well paid' 
    8   WHEN sal BETWEEN 2001 AND 3001 
    9   THEN 'Well paid' 
10   ELSE 'Overpaid' 
11   END AS pay_status 
12 FROM emp; 

ENAME  JOB  PAY_STATUS 
---------- --------- -------------------- 
SMITH  CLERK  Low paid 
ALLEN  SALESMAN Reasonably well paid 
WARD  SALESMAN Reasonably well paid 
JONES  MANAGER Well paid 
MARTIN  SALESMAN Reasonably well paid 
BLAKE  MANAGER Well paid 
CLARK  MANAGER Well paid 
SCOTT  ANALYST Well paid 
KING  PRESIDENT Overpaid 
TURNER  SALESMAN Reasonably well paid 
ADAMS  CLERK  Reasonably well paid 
JAMES  CLERK  Low paid 
FORD  ANALYST Well paid 
MILLER  CLERK  Reasonably well paid

来源

2014-09-26 Remo

您可以用'rownum'功能 – Aramillo 2014-09-26 18:28:54

可能的工作，但如果第一个条件不满足什么（IE）没有记录存在这个condn，第二个条件通行证和应只返回第二行等等。 – Remo 2014-09-26 18:32:26

'ROWNUM'会从整个结果集中随机返回有限的记录。但是，OP要为每个条件设置“DISTINCT”行。 – 2014-09-26 18:35:14

为了得到只有一个记录满足每一个条件，在SELECT声明适用DISTICT。

SQL> SELECT DISTINCT ename 2 , job 3 , CASE 4 WHEN sal < 1000 5 THEN 'Low paid' 6 WHEN sal BETWEEN 1001 AND 2000 7 THEN 'Reasonably well paid' 8 WHEN sal BETWEEN 2001 AND 3001 9 THEN 'Well paid' 10 ELSE 'Overpaid' 11 END AS pay_status 12 FROM emp;

来源

2014-09-26 18:32:40

Oracle案例陈述

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