我使用Spring Security的核心在我的web应用程序的认证,但我无法弄清楚如何从我的User类 得到一个定制的信息,这里是我的用户等级:Grails Spring Security核心 - 自定义用户信息?
package core
import beans.Colaborador
import groovy.transform.EqualsAndHashCode
import groovy.transform.ToString
@EqualsAndHashCode(includes = 'username')
@ToString(includes = 'username', includeNames = true, includePackage = false)
class Usuario implements Serializable {
private static final long serialVersionUID = 1
transient springSecurityService
String username
String password
boolean enabled = true
boolean accountExpired
boolean accountLocked
boolean passwordExpired
Colaborador colaborador
Usuario(String username, String password) {
this()
this.username = username
this.password = password
}
Set<Permissao> getAuthorities() {
UsuarioPermissao.findAllByUsuario(this)*.permissao
}
def beforeInsert() {
encodePassword()
}
def beforeUpdate() {
if (isDirty('password')) {
encodePassword()
}
}
protected void encodePassword() {
password = springSecurityService?.passwordEncoder ? springSecurityService.encodePassword(password) : password
}
static transients = ['springSecurityService']
static constraints = {
username blank: false, unique: true
password blank: false
colaborador nullable: true
}
static mapping = {
password column: '`password`'
}
}
我想要的信息如果我尝试通过使用秒来访问它:loggedInUserInfo并没有成功,我读过我需要创建一个自定义UserDetailsService,但我无法找出如何以及在哪里创造它,可以有人给我一只手吗?
谢谢!
@Edit
我试过下面的文档和我创建两个类
import beans.Colaborador
import grails.plugin.springsecurity.userdetails.GrailsUser
import org.springframework.security.core.GrantedAuthority
class MyUserDetails extends GrailsUser {
final Colaborador colaborador
MyUserDetails(String username, String password, boolean enabled,
boolean accountNonExpired, boolean credentialsNonExpired,
boolean accountNonLocked,
Collection<GrantedAuthority> authorities,
long id, Colaborador colaborador) {
super(username, password, enabled, accountNonExpired,
credentialsNonExpired, accountNonLocked, authorities, id)
this.colaborador = colaborador
}
}
和
package core
import grails.plugin.springsecurity.SpringSecurityUtils
import grails.plugin.springsecurity.userdetails.GrailsUserDetailsService
import grails.plugin.springsecurity.userdetails.NoStackUsernameNotFoundException
import grails.transaction.Transactional
import org.springframework.security.core.authority.SimpleGrantedAuthority
import org.springframework.security.core.userdetails.UserDetails
import org.springframework.security.core.userdetails.UsernameNotFoundException
class MyUserDetailsService implements GrailsUserDetailsService {
static final List NO_ROLES = [new SimpleGrantedAuthority(SpringSecurityUtils.NO_ROLE)]
UserDetails loadUserByUsername(String username, boolean loadRoles)
throws UsernameNotFoundException {
return loadUserByUsername(username)
}
@Transactional(readOnly = true, noRollbackFor = [IllegalArgumentException, UsernameNotFoundException])
UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
Usuario user = Usuario.findByUsername(username)
if (!user) throw new NoStackUsernameNotFoundException()
def roles = user.authorities
def authorities = roles.collect {
new SimpleGrantedAuthority(it.authority)
}
return new MyUserDetails(user.username, user.password, user.enabled,
!user.accountExpired, !user.passwordExpired,
!user.accountLocked, authorities ?: NO_ROLES, user.id,
user.colaborador)
}
}
,当我在我的应用登录我得到这个错误:
2016-11-14 11:56:46,061 [http-bio-80-exec-4] ERROR authentication.GrailsUsernamePasswordAuthenticationFilter - An internal error occurred while trying to authenticate the user.
Message: Could not find matching constructor for: java.lang.Object(java.lang.String, java.lang.String, java.lang.Boolean, java.lang.Boolean, java.lang.Boolean, java.lang.Boolean, java.util.ArrayList, java.lang.Long)
你只是想要访问用户类通知到另一种方法或类权利? –
我想从另一个类或视图访问自定义的用户信息,在这种情况下,来自该Colaborador对象的数据 – xSlok