1
我试图重载< <运营商,但我发现这样的一些错误:在C++中重载<<运算符?
传递
const std::ostream' as
这个 '的std :: basic_ostream < _CharT,_Traits> &的std ::说法basic_ostream < _CharT, _Traits> ::运算< <(常量无效*)[与_CharT =炭,_Traits =标准:: char_traits]”丢弃限定符
这是我的代码:
#include<iostream>
using namespace std;
class nod{
protected:
int info;
nod *next;
friend class lista;
friend const ostream &operator<<(const ostream &,lista&);
};
class lista
{nod *first, *last;
public:
lista()
{first=new nod;
last=new nod;
first=last=NULL;}
void insert(int);
// void remove();
void afisare();
nod *get_first(){ return first;};
};
void lista::insert(int x)
{ nod *nou=new nod;
nou->info=x;
if(!first)
first=last=nou;
else
nou->next=first;
first=nou;
last->next=first;}
const ostream &operator<<(const ostream &o,lista &A)
{nod *curent=new nod;
o<<"Afisare: ";
curent=A.get_first();
if(curent)
o<<curent->info<<" ";
curent=curent->next;
while(curent!=A.get_first())
{o<<curent->info<<" ";
curent=curent->next;}
return o;
}
int main()
{lista A;
A.insert(2);
A.insert(6);
A.insert(8);
A.insert(3);
A.insert(5);
cout<<A;
system("pause");
return 0;}
'operator <<'修改'cout << A;'中的'std :: cout'。这是[正确的签名](http://stackoverflow.com/questions/4421706/operator-overloading/4421719#4421719)。 – chris