Python异常：针对任何异常调用相同的函数

Question

请注意，如果抛出任何异常，将调用foobar()。有没有办法做到这一点，而不是在每个异常中使用相同的行？

try: 
    foo() 
except(ErrorTypeA): 
    bar() 
    foobar() 
except(ErrorTypeB): 
    baz() 
    foobar() 
except(SwineFlu): 
    print 'You have caught Swine Flu!' 
    foobar() 
except: 
    foobar() 

Answer 1

success = False 
try: 
    foo() 
    success = True 
except(A): 
    bar() 
except(B): 
    baz() 
except(C): 
    bay() 
finally: 
    if not success: 
     foobar() 

Answer 2

您可以使用字典来映射针对功能异常调用：

exception_map = { ErrorTypeA : bar, ErrorTypeB : baz } 
try: 
    try: 
     somthing() 
    except tuple(exception_map), e: # this catches only the exceptions in the map 
     exception_map[type(e)]() # calls the related function 
     raise # raise the Excetion again and the next line catches it 
except Exception, e: # every Exception ends here 
    foobar()